Click here to Skip to main content
11,790,816 members (53,740 online)
Rate this: bad
Please Sign up or sign in to vote.
See more: VS2008 C# WPF
i have added the context menu on list view and on click of view context i want to get the Ip address of student and on that ip add
i want to assign seperate lesson to only student of that machine plz help me.I just want how i get the IP address on which the context
menu occure and i am assigning lesson then i will using that ip send the message by using socket programming. i am posting my code here..
<window x:class="WpfApplication5.Window1" xmlns:x="#unknown">
    Title="Window1" Height="300" Width="300" Loaded="Window_Loaded">
        <listview name="ListView" itemssource="{Binding}">
                <contextmenu name="cmclass" staysopen="true" datacontext="{Binding}">
                        <outerglowbitmapeffect />
                    <menuitem header="Assign Seperate Lesson" />
                    <menuitem header="exit" />

                    <gridviewcolumn header="Position" displaymemberbinding="{Binding Position}" width="60">
                    <gridviewcolumn header="Name" displaymemberbinding="{Binding Name}">
                    <gridviewcolumn header="status" displaymemberbinding="{Binding Status}">
                    <gridviewcolumn header="Ip Address" displaymemberbinding="{Binding IPAdd}" width="100">

<pre lang="cs">using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;
using System.Collections.ObjectModel;
namespace WpfApplication5
    /// <summary>
    /// Interaction logic for Window1.xaml
    /// </summary>
    public partial class Window1 : Window
        public Window1()
            ListView.DataContext = new ObservableCollection<Person>()
                                new Person() {Position = 1, Name ="abc", Status = "Online",IPAdd=""},
                                new Person() {Position = 2, Name  = "xyz", Status = "Online",IPAdd=""},
                                new Person() {Position = 3, Name= "lmn", Status = "Online",IPAdd=""},
                                new Person() {Position= 4, Name = "pqr", Status = "Online",IPAdd=""}
        public class Person
            public int Position { get; set; }
            public string Name { get; set; }
            public string Status { get; set; }
            public string IPAdd { get; set; }
        private void Window_Loaded(object sender, RoutedEventArgs e)

Posted 30-Apr-11 2:52am
Edited 1-May-11 19:21pm

1 solution

Rate this: bad
Please Sign up or sign in to vote.

Solution 1

Your list view already displays the age in a column. So what would you achieve by that view menu?
vishal_h at 2-May-11 0:50am
thanks for prev response.sir i have change my question plz give your some inputs..

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

  Print Answers RSS
0 OriginalGriff 385
1 ppolymorphe 339
2 Richard MacCutchan 118
3 Maciej Los 70
4 George Swan 70
0 OriginalGriff 1,154
1 Maciej Los 825
2 KrunalRohit 686
3 ppolymorphe 660
4 CPallini 621

Advertise | Privacy | Mobile
Web04 | 2.8.1509028.1 | Last Updated 2 May 2011
Copyright © CodeProject, 1999-2015
All Rights Reserved. Terms of Service
Layout: fixed | fluid

CodeProject, 503-250 Ferrand Drive Toronto Ontario, M3C 3G8 Canada +1 416-849-8900 x 100