how to pass argv more than 1 in c in main method

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How to pass more than 1 argument in main method in c

VB

INT main(int argc, char *argv[])
{

    // to avoid compiler warning


    printf("\n\n\n\n");
    printf("-----------------------TEST IFD-----------------------------\n\n");

    if (argc>1)
    {
//coding
}
Now it takes 1 argument i.e. 'c' when i complile in vs 2008

Posted 7-Dec-11 23:37pm

Member 7909353

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Richard MacCutchan 8-Dec-11 5:47am

What is the compiler warning and on which line?

2 solutions

Solution 1

all arguments what ever you pass will be stored as a vector of strings to the main.
Suppose your program name is Test.exe
You write
Test.exe A B C
in command line.
So your main program gets the following parameter

C++

argv[0] = "test.exe" //This is always your program name
argv[1] = "A"
argv[2] = "B"
argv[3] = "C"

now the value of argc (Argument Count) is the total number of elements in the char** argv(Argument Vector). In the above case it is argc=4

Posted 7-Dec-11 23:49pm

BrainlessLabs.com

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Member 7909353 · Accepted Answer · 2011-12-08T02:37:00

Solution 2

insert the argument in debug in command argument in property of project.
like in command argument aaa
it is a parameter and argv[1] will be aaa

Posted 8-Dec-11 2:37am

Member 7909353

Updated 8-Dec-11 17:53pm

v3

Comments

Albert Holguin 8-Dec-11 8:55am

This isn't exactly what you asked...