i want to open newform using timer

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When timer exits i want to open Form2 but this will gives an error
"Form that is already visible cannot be displayed as a modal dialog box. Set the form's visible property to false before calling showDialog."

C#

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

namespace timer
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();

        }


        private void timer1_Tick(object sender, EventArgs e)
        {
            if (progressBar2.Value < 100)
            {
                progressBar2.Value += 2;
            }
            else
            {
                Form2 f = new Form2();
                //f.ShowDialog();
                ShowDialog(new Form2());
            }
        }
    }
}

Posted 17-Nov-12 8:09am

Member 9411249

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ridoy 17-Nov-12 14:42pm

This occurs for this line..ShowDialog(new Form2());
Whats the problem of using f.ShowDialog() instead of it?

Member 9411249 17-Nov-12 14:50pm

this gives me an error and not working means not open Form2

2 solutions

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Toli Cuturicu · Answer 1 · 2012-11-17T14:19:00

Try:

using System;
using System.Drawing;
using System.Windows.Forms;
 
namespace Timer
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
            form2 = new Form2();  // Create the form only once. The Tick event may be called thouthands of times!
        }

        private Form2 form2;

        private void timer1_Tick(object sender, EventArgs e)
        {
            if (progressBar2.Value < 100)
            {
                progressBar2.Value += 2;
            }
            else
            {
                form2.ShowDialog();
                timer1.Stop();  // We did our job. Leave the Timer alone now. You should restart the timer only if needed.
            }
        }
    }
}

anilkumar.6714 · Answer 2 · 2012-11-17T16:12:00

Hi,
lets try this

C#

using System;
using System.Drawing;
using System.Windows.Forms;
 
namespace Timer
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }
        Form2 f2= new Form2();  //creates the object for Form2
        
       private void Form1_Load(object sender, EventArgs e)
        {
          timer1.Start();//calling the timer tick event
        }
        private void timer1_Tick(object sender, EventArgs e)
        {
            if (progressBar2.Value < 100)
            {
                progressBar2.Value += 2;
            }
            else
            {
                timer1.Stop(); // Before calling f2.ShowDialog(), stops the timer event
                f2.ShowDialog();
            }
        }
    }
}

i hope this will helps to you.

i want to open newform using timer

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