how to get the target clas name inside the template

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sample code:

template <class t=""> class MyTempl1
{
public:
    void F1()
    {
      T* pT = static_cast<t*>(this);

      LPCSTR typname= pT->  xxxx;
      ATLTRACE( "%hs hello world", typname);
    }
};

class Cl1 : 
   public CComObjectRootEx<ccomsinglethreadmodel>,
   public MyTempl1<cl1>
{
};

i use ATL. and for debug log i want to write the name of the outer class "Cl1" in
the template. what can i use for xxx to get it?
Thank you Frank

Posted 12-Feb-13 4:20am

Frank Thielemann

Updated 12-Feb-13 4:40am

Matthew Faithfull

v2

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3 solutions

Solution 1

Hey.

I generally see two ways of doing what you wish (there might be more of course):

1. Use Run-Time Type Information[^], see the link for more details. You could try using the type_info[^] class' name() method.

2. Have a -potentially virtual- function in your classes that can return a string-representation of the class and implement this in every class you use with that template. E.g:

class CMyClass
{
...
virtual LPCTSTR GetClassDebugName() const { return "CMyClass"; }
...
};

...
LPCSTR typname= pT->GetClassDebugName();
...

Posted 12-Feb-13 4:37am

Code-o-mat

Solution 2

Add a typename function to Cl1 and call T::typename() from inside MyTempl1<cl1>::F1()</cl1>.
There's nothing to stop you doing that and it will ensure that any class you use as the template parameter to MyTempl1 will have to have the typename function or the code won't compile.
This is pretty much what's known as 'concept' programming or the first part of it anyway, Bjarne Stroustrup's current favourite idea so you're in good company.

Posted 12-Feb-13 4:44am

Matthew Faithfull

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__UFNHGGI_H__ · Accepted Answer · 2013-02-13T02:19:00

Solution 3

XML

template <class T> class MyTempl1
{
public:
    void F1()
    {
        const char* typname = typeid(T).name() + 6;
        printf("%s\n", typname);
    }
};
class Cl1 : public MyTempl1<Cl1>
{

};

:D

Posted 13-Feb-13 2:19am

__UFNHGGI_H__