Determining the size of array of pointers

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I am using two dimensional char array of pointers for saving list of names as follows :

int size;

char** name;
name=new char*[size];

I am reading the "size" from the user and then I am storing the names entered by the user in this array.

Now my question is through my code how can i get the size of this array, i.e I wanted to know how many names are being read?

Thankss

Posted 22-May-13 0:23am

AsthaS

Updated 22-May-13 0:25am

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Maximilien 22-May-13 8:42am

Since this is tagged as C++ , I would suggest using a vector of string instead of arrays of char*; it will help you a lot.

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Kucera Jan · Answer 1 · 2013-05-22T01:50:00

Hi,

actually you cannot do thi, because the array is allocated dynamically (= you use operator new to allocate it). As a result you have to remember the length of the array in a variable (such as size that you have) and you need to pass this size as a parameter to all methods/functions that need to be aware the size.

(If you are using this code in method of a class, you can store the size of the array in a member variable and so avoid the need to pass it to the member methods as a parameter.)

Hope this helps.

Best regards,
J.K.

CPallini · Answer 2 · 2013-05-22T01:56:00

Solution 2

There are basically two techniques, either:

(As already suggested by Kucera Jan) make a copy of the size parameter and use it when needed.

or

Add a sentinel element to the array, namely a NULL pointer at the end of the array.

Posted 22-May-13 1:56am

CPallini

Determining the size of array of pointers

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Determining the size of array of pointers

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