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Storing and Retrieving Images from SQL Server using Microsoft .NET

, 30 Jun 2005
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Storing and retrieving images from SQL Server using Microsoft .NET.

Introduction

This article is about storing and retrieving images from database in Microsoft .NET using C#.

Tools Used

  • SQL Server 2000
  • Microsoft .NET Version 1.1
  • C# (Windows Forms based application)

Storing Images

  1. Create a table in a SQL Server 2000 database which has at least one field of type IMAGE.

    Here is the script I used:

    CREATE TABLE [dbo].[tblImgData] (
    
            [ID] [int] NOT NULL ,
    
            [Name] [varchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    
            [Picture] [image] NULL 
    
    ) ON [PRIMARY] TEXTIMAGE_ON [PRIMARY]
  2. Actually IMAGE field is just holding the reference to the page containing the binary data so we have to convert our image into bytes.
    1. I used a file open dialog box to locate the file.
      this.openFileDialog1.ShowDialog(this);
      string strFn=this.openFileDialog1.FileName;
    2. By using FileInfo class, I retrieved the file size:
      FileInfo fiImage=new FileInfo(strFn);
    3. Declare an array of that size.
      this.m_lImageFileLength=fiImage.Length;
      m_barrImg=new byte[Convert.ToInt32(this.m_lImageFileLength)];
    4. By using FileStream object, I filled the byte array.
      FileStream fs=new FileStream(strFn,FileMode.Open, 
                        FileAccess.Read,FileShare.Read);
      int iBytesRead=fs.Read(m_barrImg,0,
                     Convert.ToInt32(this.m_lImageFileLength));
      fs.Close();

    Complete Load Image Code

    protected void LoadImage()
    {
        try
        {
            this.openFileDialog1.ShowDialog(this);
            string strFn=this.openFileDialog1.FileName;
            this.pictureBox1.Image=Image.FromFile(strFn);
            FileInfo fiImage=new FileInfo(strFn);
            this.m_lImageFileLength=fiImage.Length;
            FileStream fs=new FileStream(strFn,FileMode.Open, 
                              FileAccess.Read,FileShare.Read);
            m_barrImg=new byte[Convert.ToInt32(this.m_lImageFileLength)];
            int iBytesRead = fs.Read(m_barrImg,0, 
                             Convert.ToInt32(this.m_lImageFileLength));
            fs.Close();
        }
        catch(Exception ex)
        {
            MessageBox.Show(ex.Message);
        }
    }
  3. Saving byte array data to database.
    1. Create command text to insert record.
      this.sqlCommand1.CommandText= 
        "INSERT INTO tblImgData(ID,Name,Picture)" + 
        " values(@ID,@Name,@Picture)";
    2. Create parameters.
      this.sqlCommand1.Parameters.Add("@ID",
                 System.Data.SqlDbType.Int, 4);
      this.sqlCommand1.Parameters.Add("@Name", 
                 System.Data.SqlDbType.VarChar, 50);
      
      this.sqlCommand1.Parameters.Add("@Picture", 
                 System.Data.SqlDbType.Image);

      Notice “@Picture” has “SqlDbType.Image” because it is of IMAGE type Field.

    3. Provide the value to the parameters.
      this.sqlCommand1.Parameters["@ID"].Value=this.editID.Text;
      this.sqlCommand1.Parameters["@Name"].Value=this.editName.Text;
      
      this.sqlCommand1.Parameters["@Picture"].Value=this.m_barrImg;

      this.m_barrImg” is a byte array which we filled in the previous step.

    4. Now execute non-query for saving the record to the database.
      int iresult=this.sqlCommand1.ExecuteNonQuery();

    Complete Save Image Code

    private void btnSave_Click(object sender, System.EventArgs e)
    {
        try
        {
            this.sqlConnection1.Open();
            if (sqlCommand1.Parameters.Count ==0 )
            {
                this.sqlCommand1.CommandText="INSERT INTO tblImgData(ID," + 
                               " Name,Picture) values(@ID,@Name,@Picture)";
                this.sqlCommand1.Parameters.Add("@ID", 
                                 System.Data.SqlDbType.Int,4);
                this.sqlCommand1.Parameters.Add("@Name", 
                                 System.Data.SqlDbType.VarChar,50);
                this.sqlCommand1.Parameters.Add("@Picture", 
                                 System.Data.SqlDbType.Image);
            }
    
            this.sqlCommand1.Parameters["@ID"].Value=this.editID.Text;
            this.sqlCommand1.Parameters["@Name"].Value=this.editName.Text;
            this.sqlCommand1.Parameters["@Picture"].Value=this.m_barrImg;
    
            int iresult=this.sqlCommand1.ExecuteNonQuery();
            MessageBox.Show(Convert.ToString(iresult));
        }
        catch(Exception ex)
        {
            MessageBox.Show(ex.Message);
        }
        finally
        {
            this.sqlConnection1.Close();
        }
    }

Retrieving Image

Retrieving images from the database is the exact reverse process of saving images to the database.

  1. First create command text to retrieve record.
    SqlCommand cmdSelect = new SqlCommand("select Picture" + 
                           " from tblImgData where ID=@ID", 
                           this.sqlConnection1);
  2. Create parameter for the query.
    cmdSelect.Parameters.Add("@ID",SqlDbType.Int,4);
  3. Provide value to the parameter.
    cmdSelect.Parameters["@ID"].Value=this.editID.Text;
  4. Open database connection and execute “ExecuteScalar” because we want only “IMAGE” column data back.
    byte[] barrImg=(byte[])cmdSelect.ExecuteScalar();

    As the execute scalar returns data of “Object” data type, we cast it to byte array.

  5. Save this data to a temporary file.
    string strfn=Convert.ToString(DateTime.Now.ToFileTime());
    FileStream fs=new FileStream(strfn,FileMode.CreateNew,FileAccess.Write);
    fs.Write(barrImg,0,barrImg.Length);
    fs.Flush();
    fs.Close();
  6. And display the image anywhere you want to display.
    pictureBox1.Image=Image.FromFile(strfn);

Complete Image Retrieving Code

private void btnLoad_Click(object sender, System.EventArgs e)
{
    try
    {
        SqlCommand cmdSelect=new SqlCommand("select Picture" + 
              " from tblImgData where ID=@ID",this.sqlConnection1);
        cmdSelect.Parameters.Add("@ID",SqlDbType.Int,4);
        cmdSelect.Parameters["@ID"].Value=this.editID.Text;

        this.sqlConnection1.Open();
        byte[] barrImg=(byte[])cmdSelect.ExecuteScalar();
        string strfn=Convert.ToString(DateTime.Now.ToFileTime());
        FileStream fs=new FileStream(strfn, 
                          FileMode.CreateNew, FileAccess.Write);
        fs.Write(barrImg,0,barrImg.Length);
        fs.Flush();
        fs.Close();
        pictureBox1.Image=Image.FromFile(strfn);
    }
    catch(Exception ex)
    {
        MessageBox.Show(ex.Message);
    }
    finally
    {
        this.sqlConnection1.Close();
    }
}

Bibliography

License

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About the Author

Kazim Sardar Mehdi
Web Developer
Denmark Denmark
No Biography provided

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Questionquestion PinmemberMember 884454618-Apr-12 2:15 

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