
Comments and Discussions



Hi,
Thanks for reading.
I have the dll registered properly (I think), but knowing little to nothing about asp.NET ( using classic asp/ VB ) I cannot get this to work.
Can anyone give me a simple example of how to call the dll from a .aspx page and get the creationDate from a specific jpg?
Thanks a lot!






I am using your code for a little personal tool and I was trying to rename the image file after taking the ExIf information. The problem is, the file always locked and I looked at your code it looks like you're not handling the stream pretty well which costs the file to lock the entire runtime so here's a little fix of your code.
Instead of leaving the stream open, copy the stream on a new stream (MemoryStream) and use that MemoryStream on the Image.
public static PropertyItem[] GetExifProperties(string fileName)
{
MemoryStream ms = new MemoryStream();
using (FileStream stream = new FileStream(fileName, FileMode.Open, FileAccess.Read))
{
stream.CopyTo(ms);
}
System.Drawing.Image image = System.Drawing.Image.FromStream(ms,
true,
false);
return image.PropertyItems;
}
Software Developer
Jayzon Ragasa
Baguio City, Philippines





Saved me soooo much time.








Im working on a website about photos... which already runs with this guy right here (jquery plug and show...) I wonder how to implement and use the same class to display the exif data for (each) & all those photos from catalogs....
ANY ideea would be realy apreciated, i'm new to .net and c# ((
thanks





Can I use some kind of a ffmpeg mono wrapper to convert videos?
modified on Wednesday, September 21, 2011 6:09 AM





Hi!
I used the dll and it works great so far.
Now I want to change the recording date ("Aufnahmedatum" in German) which is shown in windows 7 as info in the explorer when the image is selected.
I tried to change DTOrig, DTDigitized and Date Time but none of those is the right entry.
Does anyone know which one that is?
Thanks for any help,
Herb
Herb





Thanks for sharing! Steve Jobs needs to adopt your attitude.





Does exactly what it says it would, is well documented, is freely available.







try to update the GetExifProperties method and rebuild the solution
public static PropertyItem[] GetExifProperties(string fileName)
{
using (FileStream stream = new FileStream(fileName, FileMode.Open, FileAccess.Read))
{
System.Drawing.Image image = System.Drawing.Image.FromStream(
stream,
true,
false);
return image.PropertyItems;
}
}





Excellent work man!
was working hard for such a class of my own for my software... but u got it right!! great help!





When Im trying to get the exposure time it returns zero, I expected it to return 1/180 sec or something like that. I have uploaded a test picture, and it can be found here: http://qaz.dk/nydraabe.jpg
I also tried to get shutter speed but i returns null.





I uncomented example code and set path to my own jpg.
When THIS LINE
er.setTag(0x320, "http://www.beautifulpakistan.com");
was calling, exception System.ArgumentException was thrown in this function.
private static PropertyItem CreatePropertyItem(short type, int tag, int len, byte[] value)
{
PropertyItem item;
Assembly assembly = Assembly.GetExecutingAssembly();
Stream emptyBitmapStream = assembly.GetManifestResourceStream("EXIFextractor.decoy.jpg");
System.Drawing.Image empty = System.Drawing.Image.FromStream(emptyBitmapStream);
item = empty.PropertyItems[0];
item.Type = type;
item.Len = len;
item.Id = tag;
item.Value = new byte[value.Length];
value.CopyTo(item.Value, 0);
return item;
}
emptyBitmapStream was null.
What is wrong?





If a picture has 1/125 shutter speed, your code wil return 1/125.37 instead.





I cannot find the way of doing that because image.PropertyItems doesn't exist in CF.
Thanks





For those of you who require the GPS info. In the EXIFextractor.cs after
//5 = RATIONAL Two LONGs. The first LONG is the numerator and the second LONG expresses the//denominator.,
else if( p.Type == 0x5 )
{
I inserted this:
…
else if( p.Type == 0x5 )
{
//My code starts here
if (p.Id == 0x0004)
{
//lat
// rational
byte[] deg = new byte[4];
byte[] degdiv = new byte[4];
byte[] min = new byte[4];
byte[] mindiv = new byte[4];
byte[] sec = new byte[4];
byte[] secdiv = new byte[4];
Array.Copy(p.Value, 0, deg, 0, 4);
Array.Copy(p.Value, 4, degdiv, 0, 4);
Array.Copy(p.Value, 8, min, 0, 4);
Array.Copy(p.Value, 12, mindiv, 0, 4);
Array.Copy(p.Value, 16, sec, 0, 4);
Array.Copy(p.Value, 20, secdiv, 0, 4);
double a = convertToInt32U(deg);
double b = convertToInt32U(degdiv);
double c = convertToInt32U(min);
double d = convertToInt32U(mindiv);
double e = convertToInt32U(sec);
double f = convertToInt32U(secdiv);
double o =((a/b) + ((c/b)/60) + ((e/f)/3600));
v = o.ToString();
// Rational r = new Rational(a, b);
}
else if (p.Id == 0x0002)
{
//long
byte[] deg = new byte[4];
byte[] degdiv = new byte[4];
byte[] min = new byte[4];
byte[] mindiv = new byte[4];
byte[] sec = new byte[4];
byte[] secdiv = new byte[4];
Array.Copy(p.Value, 0, deg, 0, 4);
Array.Copy(p.Value, 4, degdiv, 0, 4);
Array.Copy(p.Value, 8, min, 0, 4);
Array.Copy(p.Value, 12, mindiv, 0, 4);
Array.Copy(p.Value, 16, sec, 0, 4);
Array.Copy(p.Value, 20, secdiv, 0, 4);
double a = convertToInt32U(deg);
double b = convertToInt32U(degdiv);
double c = convertToInt32U(min);
double d = convertToInt32U(mindiv);
double e = convertToInt32U(sec);
double f = convertToInt32U(secdiv);
double o = ((a / b) + ((c / b) / 60) + ((e / f) / 3600));
v = o.ToString();
}
//My Code ends here
else
{
// rational
byte[] n = new byte[p.Len / 2];
…
Not perfect but it returns valid coordinates
Some Info on how this works:
The GPS coordinates come in as rational byte arrays
d d d d x x x x m m m m x x x x s s s s x x x x
55 0 0 0 1 0 0 0 37 22 0 0 100 0 0 0 0 0 0 0 1 0 0 0
55.94483 is...
55 0 0 0 = 55 / 1 = 55 Degrees
1 0 0 0
37 22 0 0 = 5669 / 100 = 56.69 Minutes (56.69 Minutes / 60 = 0.94483 Degrees)
100 0 0 0
0 0 0 0 = 0 / 1 = 0.0 Seconds (0 Seconds / 3600 = 0 Degrees)
1 0 0 0
modified on Thursday, April 24, 2008 7:11 AM





Thanks a lot!! It works great





This is great, many thanks. I added the code you posted for GPS data, but it doesnt seem to recognise the sign, ie. 117 degrees or +117 degrees? Will look at this, but any ideas appreciated.
Rob





Ok, you can figure out if it is + or minus by reading the Gps LongitudeRef or Gps LatitudeRef.





For all Germans who need a conversion from WGS84 to Gauss Krueger I post my solution which works great:
public Int16 Transform_WGS84_2_GK ( double rLatDec, double rLonDec, double rH, ref double rLongitude, ref double rLatitude)
{
double rWGS_a = 6378137.000;
double rWGS_b = 6356752.314;
double Bessel_a = 6377397.155;
double Bessel_b = 6356078.962;
double TPdx = 598.1;
double TPdy = 73.7;
double TPdz = 418.2;
double TPex = 0.202;
double TPey = 0.045;
double TPez = 2.455;
double TPm = 6.7;
double rWGS_E2, rWGS_N;
double rVecX, rVecY, rVecZ;
double F2, F3, F4, F5, F6, F7, F8;
double rotVec1,rotVec2, rotVec3;
double trans1, trans2, trans3;
double s5;
double T5;
double B5;
double L5;
double N5;
double h5,B,L,h;
double Bessel_e2;
double n6, alpha, beta, gamma, delta, epsilon;
int L0;
double l6, B6, N6_, nano, t6;
double Bogenlaenge;
double h1,h2,r1,r2;
rWGS_E2 = ( Sqr(rWGS_a)  Sqr(rWGS_b))/ (Sqr(rWGS_a));
rWGS_N = (rWGS_a)/(Math.Sqrt( 1  rWGS_E2*Sqr(Math.Sin( rLatDec/180*Math.PI))));
rVecX = (rWGS_N + rH) * Math.Cos(rLatDec / 180 * Math.PI) * Math.Cos(rLonDec / 180 * Math.PI);
rVecY = (rWGS_N + rH) * Math.Cos(rLatDec / 180 * Math.PI) * Math.Sin(rLonDec / 180 * Math.PI);
rVecZ = ( rWGS_N * Sqr(rWGS_b)/Sqr( rWGS_a) + rH) * Math.Sin( rLatDec / 180 * Math.PI);
F5 = TPex * Math.PI / 180 / 3600;
F6 = TPey * Math.PI / 180 / 3600;
F7 = TPez * Math.PI / 180 / 3600;
F8 = 1  TPm/1000000;
F2 = ( TPdx + F7*TPdy  F6*TPdz);
F3 = (F7*TPdx + TPdy + F5*TPdz);
F4 = ( F6*TPdx  F5*TPdy + TPdz);
rotVec1 = ( rVecX + F7*rVecY  F6*rVecZ) * F8;
rotVec2 = (F7*rVecX + rVecY + F5*rVecZ) * F8;
rotVec3 = ( F6*rVecX  F5*rVecY + rVecZ) * F8;
trans1 = rotVec1 + F2;
trans2 = rotVec2 + F3;
trans3 = rotVec3 + F4;
s5 = Math.Sqrt(Sqr(trans1) + Sqr(trans2));
Bessel_e2 = (Sqr(Bessel_a)Sqr(Bessel_b))/Sqr(Bessel_a);
T5 = Math.Atan( trans3 * Bessel_a / (s5 * Bessel_b));
B5 = Math.Atan((trans3 + Bessel_e2 * Sqr(Bessel_a) / Bessel_b * Math.Pow(Math.Sin(T5), 3)) / (s5  Bessel_e2 * Bessel_a * Math.Pow(Math.Cos(T5), 3)));
L5 = Math.Atan( trans2 / trans1);
N5 = Bessel_a/Math.Sqrt(1Bessel_e2 * Sqr(Math.Sin(B5)));
h5 = (s5 / Math.Cos(B5))  N5;
B = B5 * 180 / Math.PI;
L = L5 * 180 / Math.PI;
h = h5;
n6 = (Bessel_a  Bessel_b)/(Bessel_a + Bessel_b);
alpha = ((Bessel_a + Bessel_b)/2) * ( 1 + 0.25*Sqr(n6) + 1/64*Math.Pow(n6,4));
beta = 1.5*n6 + 9/16*Math.Pow(n6,3)  3/32*Math.Pow(n6,5);
gamma = 15/16 * Sqr(n6)  15/32*Math.Pow(n6,4);
delta = 35/48*Math.Pow(n6,3) + 105/256*Math.Pow(n6,5);
epsilon = 315/512*Math.Pow(n6,4);
if( Math.Abs(L6) < 1.5)
L0 = 6;
else if (Math.Abs(L  9) < 1.5)
L0 = 9;
else if (Math.Abs(L  12) < 1.5)
L0 = 12;
else if (Math.Abs(L  15) < 1.5)
L0 = 15;
else
{
MessageBox.Show( "Länge nicht unterstützt! Koordinatentransformation nur für Deutschland!");
L0 = 1;
}
if (L0 > 0)
{
l6 = (L  L0) * Math.PI / 180;
B6 = B * Math.PI / 180;
N6_ = Bessel_a / Math.Sqrt(1  Bessel_e2 * Sqr(Math.Sin(B6)));
nano = Math.Sqrt(Sqr(Bessel_a) / Sqr(Bessel_b) * Bessel_e2 * Sqr(Math.Cos(B6)));
t6 = Math.Tan(B6);
Bogenlaenge = alpha * (B6 + beta * Math.Sin(2 * B6) + gamma * Math.Sin(4 * B6) + delta * Math.Sin(6 * B6) + epsilon * Math.Sin(8 * B6));
h1 = t6 / 2 * N6_ * Sqr(Math.Cos(B6)) * Sqr(l6);
h2 = t6 / 24 * N6_ * Math.Pow(Math.Cos(B6), 4) * (5  Sqr(t6) + 9 * Sqr(nano) + 4 * Math.Pow(nano, 4)) * Math.Pow(l6, 4);
// h3 := t6/720*N6_*Power(Cos(B6),6)*(61  58*Sqr(t6) + 270*Sqr(nano)  330*Sqr(t6)*Sqr(nano))*Power(l6,6);
// h4 := t6/40320*N6_*Power(Cos(B6),8)*(13853111*Sqr(t6) + 543*Power(t6,4)  Power(t6,6))*Power(l6,8);
rLatitude = Bogenlaenge + h1 + h2;
r1 = N6_ * Math.Cos(B6) * l6;
r2 = N6_ / 6 * Math.Pow(Math.Cos(B6), 3) * (1  Sqr(t6) + Sqr(nano)) * Math.Pow(l6, 3);
rLongitude = r1 + r2 + 500000 + L0 / 3 * 1000000;
}
return 0;
}
private double Sqr(double r)
{
return ( Math.Pow( r, 2.0));
}







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EXIFextractor library to extract EXIF information.
Type  Article 
Licence  
First Posted  13 Aug 2005 
Views  276,503 
Bookmarked  166 times 

