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Evaluate C# Code (Eval Function)

By , 12 Oct 2005
 

Sample Image - EvalCSCode.jpg

Introduction

This example shows an "Eval" function for C# and implements different usages of this evaluate function. The library is written in C# and can be tested with the MainForm in the solution.

Source view

Here you will see all the trick. The code generates a class structure with a basic "function prototype" in which the code to evaluate is filled in. The execution of the function should execute your code:

// Eval > Evaluates C# sourcelanguage
public static object Eval(string sCSCode) {

  CSharpCodeProvider c = new CSharpCodeProvider();
  ICodeCompiler icc = c.CreateCompiler();
  CompilerParameters cp = new CompilerParameters();

  cp.ReferencedAssemblies.Add("system.dll");
  cp.ReferencedAssemblies.Add("system.xml.dll");
  cp.ReferencedAssemblies.Add("system.data.dll");
  cp.ReferencedAssemblies.Add("system.windows.forms.dll");
  cp.ReferencedAssemblies.Add("system.drawing.dll");

  cp.CompilerOptions = "/t:library";
  cp.GenerateInMemory = true;

  StringBuilder sb = new StringBuilder("");
  sb.Append("using System;\n" );
  sb.Append("using System.Xml;\n");
  sb.Append("using System.Data;\n");
  sb.Append("using System.Data.SqlClient;\n");
  sb.Append("using System.Windows.Forms;\n");
  sb.Append("using System.Drawing;\n");

  sb.Append("namespace CSCodeEvaler{ \n");
  sb.Append("public class CSCodeEvaler{ \n");
  sb.Append("public object EvalCode(){\n");
  sb.Append("return "+sCSCode+"; \n");
  sb.Append("} \n");
  sb.Append("} \n");
  sb.Append("}\n");

  CompilerResults cr = icc.CompileAssemblyFromSource(cp, sb.ToString());
  if( cr.Errors.Count > 0 ){
      MessageBox.Show("ERROR: " + cr.Errors[0].ErrorText, 
         "Error evaluating cs code", MessageBoxButtons.OK, 
         MessageBoxIcon.Error );
      return null;
  }

  System.Reflection.Assembly a = cr.CompiledAssembly;
  object o = a.CreateInstance("CSCodeEvaler.CSCodeEvaler");

  Type t = o.GetType();
  MethodInfo mi = t.GetMethod("EvalCode");

  object s = mi.Invoke(o, null);
  return s;

}

Thanks fly out to:

Credits:

  • Kim Hauser (dave) - Application Developer & System Engineer.

License

This article, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

About the Author

kim.david.hauser
Software Developer (Senior)
Switzerland Switzerland
Member
programmer and software junkie since 1991 zurich switzerland

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GeneralAwesome, though quick questionmembermbainrot10 Apr '09 - 21:03 

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