# Approximate String Matching - Row-wise Bit-parallelism Algorithm (BPR)

, 14 Nov 2010 CPOL
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One of the best methods for solving approximate string matching problem

## Introduction

Approximate `string `matching, also called "`string `matching allowing errors", is the problem of finding a pattern p in a text T when a limited number k of differences is permitted between the pattern and its occurrences in the text.

## Solutions

The oldest solution to the problem relies on dynamic programming. For example, see Levenstein distance implementation on Code Project (www.codeproject.com/KB/recipes/fuzzysearch.aspx) or in Wikipedia(http://en.wikipedia.org/wiki/Fuzzy_string_searching).

An alternative and very useful way to consider the approximate search problem is to model the search with a nondeterministic finite automaton (NFA). Consider the NFA for k = 2 errors. Every row denotes the number of errors seen. Every column represents matching a pattern prefix. Horizontal arrows represent matching a character (i.e., if the pattern and text characters match, we advance in the pattern and in the text). All the others increment the number of errors by moving to the next row: Vertical arrows insert a character in the pattern (we advance in the text but not in the pattern), short diagonal arrows substitute a character (we advance in the text and pattern), and long diagonal arrows delete a character of the pattern (they are e-transitions, since we advance in the pattern without advancing in the text). The initial self-loop allows an occurrence to start anywhere in the text. The automaton signals (the end of) an occurrence whenever a rightmost state is active.

## BPR Algorithm

Bit-parallel algorithms are a simple and fast way to encode NFA states thanks to their higher locality of reference. Here is the pseudo-code for this algorithm that is described in the book "Flexible Pattern Matching in Strings" (see References for more information).

```BPR (p = p1p2...pm, T = t1t2...tn, k)
1.    Preprocessing
2.        For c e S Do B[c] <- 0m
3.        For j e 1 ... m Do B[pj] <- B[pj] | 0m-j10j-1
4.    Searching
5.       For i e 0 ... k Do Ri <- 0m-i1i
6.       For pos e 1 ... n Do
7.            oldR <- R0
8.            newR <- ((oldR << 1) | 1) & B[tpos]
9.            R0 <- newR
10.           For i e 1 ... k Do
11.              newR <- ((Ri << 1) & B[tpos]) | oldR | ((oldR | newR) << 1)
12.              oldR <- Ri, Ri <- newR
13.           End of for
14.           If newR & 10m-1 <> 0 Then report an occurrence at pos
15.      End of for```

For example, let's search for pattern "`rain`" in "`brain`" text with 2 errors. We start with B=

 r 0001 a 0010 i 0100 n 1000 * 0000

and { R0=0000 R1=0001 R2=0011 }. And here is step by step run:

b - 0000

R0- 0000

R1- 0000

R2- 0011

r - 0001

R0- 0001

R1- 0010

R2- 0100

a - 0010

R0- 0010

R1- 0111

R2- 1110

Occurrence at position 3

i - 0100

R0- 0100

R1- 1110

R2- 11111

Occurrence at position 4

n - 1000

R0- 1000

R1- 1100

R2- 1110

Occurrence at position 5

## C# Implementation

```public static void BPR(string pattern, string text, int errors)
{
int[] B = new int[ushort.MaxValue];
for (int i = 0; i < ushort.MaxValue; i++) B[i] = 0;
// Initialize all characters positions
for (int i = 0; i < pattern.Length; i++)
{
B[(ushort)pattern[i]] |= 1 << i;
}
// Initialize NFA states
int[] states = new int[errors+1];
for(int i= 0; i <= errors; i++)
{
states[i] = (i == 0) ? 0 : (1 << (i - 1) | states[i-1]);
}
//
int oldR, newR;
int exitCriteria = 1 << pattern.Length -1;

for (int i = 0; i < text.Length; i++)
{
oldR = states[0];
newR = ((oldR << 1) | 1) & B[text[i]];
states[0] = newR;

for (int j = 1; j <= errors; j++)
{
newR = ((states[j] << 1) & B[text[i]]) | oldR | ((oldR | newR) << 1);

oldR = states[j];
states[j] = newR;
}

if ((newR & exitCriteria) != 0)
Console.WriteLine("Occurrence at position {0}", i+1);

}
} ```

## Share

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Israel
Name: Statz Dima
Fields of interest: software

 First Prev Next
 My vote of 4 WhiteRose1611 23-Nov-10 6:50
 Re: My vote of 4 Dima Statsenko 24-Nov-10 0:13
 Re: My vote of 4 codeprojectqas 24-Nov-10 1:15
 Re: My vote of 4 Dima Statsenko 24-Nov-10 1:27
 Thanks a lot for 0.02\$ Any amount of money is really appreciated.   1) You are perfectly right, the runtime optimizes the performance of 32-bit integer types. And thats why B is defined as int[]. The length of B equals to ushort.MaxValue, because it is char values range.   2) Totally agree with you.   Dima S
 Re: My vote of 4 Richard Deeming 24-Nov-10 10:18
 Re: My vote of 4 Dima Statsenko 15-Dec-10 3:59
 My vote of 5 Mark Jerde 9-Nov-10 3:28
 Short and sweet, but.. `leppie` 9-Nov-10 0:02
 Re: Short and sweet, but.. Dima Statsenko 24-Nov-10 0:17
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