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First Posted 20 Jun 2006
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Generate SQL INSERT commands programmatically

By | 29 Jun 2006 | Article
A class for automatically generating SQL INSERT for Typed Datasets.
 
Part of The SQL Zone sponsored by
See Also

Introduction

When you use TableAdapters in C#, VS generates INSERT, SELECT, and UPDATE etc. commands for you. Other commands can be added by going into the DataSet Designer and adding commands via the Add SQL Wizard. Sometimes, however, you need additional SQL commands that contain a complete list of all the fields in the DataSet. You would also like these lists to be automatically updated whenever a change is made to the database.

The code presented here does this by using functions in the Designer code to generate such strings.

Background

I actually developed these functions because I needed to INSERT rows into a database and get the value of the Identity column on the fly as I tab through a DataGridView adding new rows.

Note that this has only been developed for simple functions, but the basics are generally applicable for other applications.

Description

The file GenerateSQL.cs contains the code for a static class GenerateSQL, which has the following functions:

  • public static string BuildAllFieldsSQL ( DataTable table )
  • Returns a list of all the columns in the DataTable in SQL format which can be used in a SELECT command etc. E.g.: CustomerID, CustomerName, ....

  • public static string BuildInsertSQL ( DataTable table )
  • Returns an INSERT command with an optional SELECT CAST statement to get the SCOPE_IDENTITY if required. E.g.: INSERT INTO tableName ( CustomerName,...) VALUES (@CustomerName,...); SELECT CAST(scope_identity() AS int ). (Note that in this example, CustomerID is an Identity so it isn't included in the string.)

  • public static SqlCommand CreateInsertCommand ( DataRow row )
  • Given a DataRow, creates an instance of SqlCommand to insert the data into the DataSet.

  • public static object InsertDataRow ( DataRow row, string connectionString )
  • Given the DataRow and a connection string, creates the SqlCommand as above and executes it, returning the identity of the record.

    For example, if the Dataset Sesigner has defined a row like:

    QfrsDataSet.MembersRow row;

    I can insert it into the database, getting the identity with the statement:

    int id = (int) GenSQL.GenerateSQL.InsertDataRow ( row, connectionString );

Here is the complete code:

using System;
using System.Text;
using System.Data;
using System.Data.OleDb;
using System.Data.SqlClient;

namespace GenSQL
{
  public static class GenerateSQL
  {
    // Returns a string containing all the fields in the table

    public static string BuildAllFieldsSQL ( DataTable table )
    {
      string sql = "";
      foreach ( DataColumn column in table.Columns )
      {
        if ( sql.Length > 0 )
          sql += ", ";
         sql += column.ColumnName;
      }
      return sql;
                }

    // Returns a SQL INSERT command. Assumes autoincrement is identity (optional)

  public static string BuildInsertSQL ( DataTable table )
  {
    StringBuilder sql = new StringBuilder ( "INSERT INTO " + table.TableName + " (" );
    StringBuilder values = new StringBuilder ( "VALUES (" );
    bool bFirst = true;
    bool bIdentity = false;
    string identityType = null;

    foreach ( DataColumn column in table.Columns )
    {
      if ( column.AutoIncrement )
      {
        bIdentity = true;

        switch ( column.DataType.Name )
        {
          case "Int16":
            identityType = "smallint";
            break;
          case "SByte":
            identityType = "tinyint";
            break;
          case "Int64":
            identityType = "bigint";
            break;
          case "Decimal":
            identityType = "decimal";
            break;
          default:
            identityType = "int";
          break;
         }
      }
      else
      {
        if ( bFirst )
          bFirst = false;
        else
        {
          sql.Append ( ", " );
          values.Append ( ", " );
        }

        sql.Append ( column.ColumnName );
       values.Append ( "@" );
        values.Append ( column.ColumnName );
      }
    }
    sql.Append ( ") " );
    sql.Append ( values.ToString () );
    sql.Append ( ")" );

    if ( bIdentity )
    {
      sql.Append ( "; SELECT CAST(scope_identity() AS " );
      sql.Append ( identityType );
      sql.Append ( ")" );
    }

    return sql.ToString (); ;
  }


    // Creates a SqlParameter and adds it to the command

    public static void InsertParameter ( SqlCommand command,
                                         string parameterName,
                                         string sourceColumn,
                                         object value )
    {
      SqlParameter parameter = new SqlParameter ( parameterName, value );

      parameter.Direction = ParameterDirection.Input;
      parameter.ParameterName = parameterName;
      parameter.SourceColumn = sourceColumn;
      parameter.SourceVersion = DataRowVersion.Current;

      command.Parameters.Add ( parameter );
    }

    // Creates a SqlCommand for inserting a DataRow
    public static SqlCommand CreateInsertCommand ( DataRow row )
    {
      DataTable table = row.Table;
      string sql = BuildInsertSQL ( table );
      SqlCommand command = new SqlCommand ( sql );
      command.CommandType = System.Data.CommandType.Text;

      foreach ( DataColumn column in table.Columns )
      {
        if ( !column.AutoIncrement )
        {
          string parameterName = "@" + column.ColumnName;
          InsertParameter ( command, parameterName, 
                            column.ColumnName, 
                            row [ column.ColumnName ] );
        }
      }
      return command;
    }

    // Inserts the DataRow for the connection, returning the identity
    public static object InsertDataRow ( DataRow row, string connectionString )
    {
      SqlCommand command = CreateInsertCommand ( row );

      using ( SqlConnection connection = new SqlConnection ( connectionString ) )
      {
        command.Connection = connection;
        command.CommandType = System.Data.CommandType.Text;
        connection.Open ();
        return command.ExecuteScalar ();
      }
    }

  }
}

Using the Code

Just include the source file in your program and call the functions. The (extremely basic) sample program uses the Northwind code files, but does not connect to it.

License

This article, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

About the Author

Ian Semmel

Web Developer

Australia Australia

Member

I have been programming for about 100 years (42 actually) and have just moved in to C# and SQL.
 
My main work nowdays involves MFC, but I do a bit of Linux/Unix stuff in C++.

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Comments and Discussions

 
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Suggestion1 small change Pinmemberleote1:22 11 Apr '12  
GeneralMy vote of 5 Pinmembereibbed15:26 10 Aug '11  
GeneralThanks a lot Pinmemberashu khanna7:43 22 Apr '11  
GeneralUnable to use InsertDataRow Pinmemberkellylc21:26 20 Sep '07  
GeneralRe: Unable to use InsertDataRow PinmemberIan Semmel10:16 25 Sep '07  
GeneralVisual Basic Version of the Code (included) PinmemberDan_Bruton15:55 5 Aug '07  
GeneralThank You PinmemberLev Vayner.4:45 31 Jul '07  
Questiondestination field is of a different data type Pinmemberkissa498:23 29 Jun '07  
Generalinsert datatable into SQL SERVER table using single query Pinmemberrajnish_haldiya22:48 12 Jun '07  
GeneralRe: insert datatable into SQL SERVER table using single query PinmemberIan Semmel10:28 13 Jun '07  
GeneralRe: insert datatable into SQL SERVER table using single query Pinmemberrajnish_haldiya0:26 14 Jun '07  
GeneralRe: insert datatable into SQL SERVER table using single query PinmemberLev Vayner.10:01 30 Jul '07  
GeneralRe: insert datatable into SQL SERVER table using single query Pinmemberrajnish_haldiya21:06 31 Jul '07  
GeneralRe: insert datatable into SQL SERVER table using single query PinmemberLev Vayner.5:30 24 Sep '07  
GeneralUsing GUID Pinmemberppro14:54 2 Feb '07  
If one added identiy type GUID will it work?
It was late and I did not read the comments couple lines down.
Disregard.
QuestionProblem with Identity Pinmembergregoryayca4:10 29 Nov '06  
QuestionWhat about binary data? PinmemberMcGahanFL9:46 20 Oct '06  
NewsTry SqlCommandBuilder class PinmemberAbishek Bellamkonda20:36 25 Jun '06  
GeneralRe: Try SqlCommandBuilder class PinmemberIan Semmel21:29 27 Jun '06  
GeneralRe: Try SqlCommandBuilder class PinmemberAbishek Bellamkonda21:43 27 Jun '06  
GeneralRe: Try SqlCommandBuilder class PinmemberStumper3:45 7 Jul '06  
GeneralStringBuilder PinmemberSteve Hansen1:11 21 Jun '06  
GeneralRe: StringBuilder PinmemberBernhard Hofmann1:54 21 Jun '06  
Generalone question.. PinmemberGuido_d22:43 20 Jun '06  
GeneralRe: one question.. PinmemberAbishek Bellamkonda20:27 25 Jun '06  

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