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A C# Implementation of Douglas-Peucker Line Approximation Algorithm

By , 6 Jun 2007
 

Introduction

I have found multiple implementations of the Douglas-Peucker algorithm but not in any .NET language, so I decided to port it over. Jonathan de Halleux has a wonderful explanation here.

Background

I needed to reduce polygons size to display on a map based on zoom levels.

Using the Code

The code included is complete and should run out of the box in Visual Studio 2005.
If it does not, please let me know.

/// <summary>
/// Uses the Douglas Peucker algorithm to reduce the number of points.
/// </summary>
/// <param name="Points">The points.</param>
/// <param name="Tolerance">The tolerance.</param>
/// <returns></returns>
public static List<Point> DouglasPeuckerReduction
    (List<Point> Points, Double Tolerance)
{
    if (Points == null || Points.Count < 3)
    return Points;

    Int32 firstPoint = 0;
    Int32 lastPoint = Points.Count - 1;
    List<Int32> pointIndexsToKeep = new List<Int32>();

    //Add the first and last index to the keepers
    pointIndexsToKeep.Add(firstPoint);
    pointIndexsToKeep.Add(lastPoint);

    //The first and the last point cannot be the same
    while (Points[firstPoint].Equals(Points[lastPoint]))
    {
        lastPoint--;
    }

    DouglasPeuckerReduction(Points, firstPoint, lastPoint, 
    Tolerance, ref pointIndexsToKeep);

    List<Point> returnPoints = new List<Point>();
    pointIndexsToKeep.Sort();
    foreach (Int32 index in pointIndexsToKeep)
    {
        returnPoints.Add(Points[index]);
    }

    return returnPoints;
}
    
/// <summary>
/// Douglases the peucker reduction.
/// </summary>
/// <param name="points">The points.</param>
/// <param name="firstPoint">The first point.</param>
/// <param name="lastPoint">The last point.</param>
/// <param name="tolerance">The tolerance.</param>
/// <param name="pointIndexsToKeep">The point index to keep.</param>
private static void DouglasPeuckerReduction(List<Point> 
    points, Int32 firstPoint, Int32 lastPoint, Double tolerance, 
    ref List<Int32> pointIndexsToKeep)
{
    Double maxDistance = 0;
    Int32 indexFarthest = 0;
    
    for (Int32 index = firstPoint; index < lastPoint; index++)
    {
        Double distance = PerpendicularDistance
            (points[firstPoint], points[lastPoint], points[index]);
        if (distance > maxDistance)
        {
            maxDistance = distance;
            indexFarthest = index;
        }
    }

    if (maxDistance > tolerance && indexFarthest != 0)
    {
        //Add the largest point that exceeds the tolerance
        pointIndexsToKeep.Add(indexFarthest);
    
        DouglasPeuckerReduction(points, firstPoint, 
        indexFarthest, tolerance, ref pointIndexsToKeep);
        DouglasPeuckerReduction(points, indexFarthest, 
        lastPoint, tolerance, ref pointIndexsToKeep);
    }
}

/// <summary>
/// The distance of a point from a line made from point1 and point2.
/// </summary>
/// <param name="pt1">The PT1.</param>
/// <param name="pt2">The PT2.</param>
/// <param name="p">The p.</param>
/// <returns></returns>
public static Double PerpendicularDistance
    (Point Point1, Point Point2, Point Point)
{
    //Area = |(1/2)(x1y2 + x2y3 + x3y1 - x2y1 - x3y2 - x1y3)|   *Area of triangle
    //Base = v((x1-x2)²+(x1-x2)²)                               *Base of Triangle*
    //Area = .5*Base*H                                          *Solve for height
    //Height = Area/.5/Base

    Double area = Math.Abs(.5 * (Point1.X * Point2.Y + Point2.X * 
    Point.Y + Point.X * Point1.Y - Point2.X * Point1.Y - Point.X * 
    Point2.Y - Point1.X * Point.Y));
    Double bottom = Math.Sqrt(Math.Pow(Point1.X - Point2.X, 2) + 
    Math.Pow(Point1.Y - Point2.Y, 2));
    Double height = area / bottom * 2;

    return height;
    
    //Another option
    //Double A = Point.X - Point1.X;
    //Double B = Point.Y - Point1.Y;
    //Double C = Point2.X - Point1.X;
    //Double D = Point2.Y - Point1.Y;
    
    //Double dot = A * C + B * D;
    //Double len_sq = C * C + D * D;
    //Double param = dot / len_sq;
    
    //Double xx, yy;
    
    //if (param < 0)
    //{
    //    xx = Point1.X;
    //    yy = Point1.Y;
    //}
    //else if (param > 1)
    //{
    //    xx = Point2.X;
    //    yy = Point2.Y;
    //}
    //else
    //{
    //    xx = Point1.X + param * C;
    //    yy = Point1.Y + param * D;
    //}
    
    //Double d = DistanceBetweenOn2DPlane(Point, new Point(xx, yy));
}

Points of Interest

The code is not overly complicated. It was fun to port this algorithm, since all I feel I do now a days is hold business' hands to help them try and solve business problems that there is no consensus on.

History

  • Beta 1

License

This article, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

About the Author

CraigSelbert
Web Developer
United States United States
Member
No Biography provided

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Question1 bug, + 1 potential bug [modified]membergyuri1023 Apr '12 - 22:45 
AnswerRe: 1 bug, + 1 potential bugmembertplokas26 Mar '13 - 13:46 
QuestionUseful,Thanks!membermasy19112 Mar '12 - 22:43 
I really need it,thank you very much!
QuestionGreat Job!membercdrake19 Dec '11 - 7:32 
Generalhow calculate an epsilon valuememberunravel-the-sky23 May '11 - 5:52 
GeneralSome Issues with your implementationmembermatthew minke15 Jul '10 - 10:57 
GeneralVery useful thanks - Point number reduction (Max Distance relevant tolerance) [modified]memberkamyk3 Mar '10 - 22:05 
GeneralVery useful thanksmemberdylanhayes17 Nov '09 - 1:35 
GeneralThanks!memberMember 337866727 Mar '09 - 9:28 
QuestionAnd other functions from Plot Graphic Library?memberagorby28 Apr '08 - 2:28 
GeneralperpendicularmemberAlex Bespalov22 Dec '07 - 20:23 
GeneralperpendicularmemberAlex Bespalov22 Dec '07 - 20:21 
GeneralDo you know offhand if the result of this algorithm is the same/different....membersherifffruitfly6 Jun '07 - 11:28 
GeneralRe: Do you know offhand if the result of this algorithm is the same/different....memberCraigSelbert6 Jun '07 - 15:27 
GeneralCode questionmemberDocJim4 Jun '07 - 8:46 
GeneralRe: Code questionmemberCraigSelbert6 Jun '07 - 8:30 
GeneralNeat...Yeah...New algorithmmemberjconwell25 May '07 - 4:50 
GeneralRe: Neat...Yeah...New algorithmmemberCraigSelbert25 May '07 - 15:40 
GeneralTake a look herememberD_Guidi25 May '07 - 3:32 
GeneralRe: Take a look herememberCraigSelbert25 May '07 - 15:49 

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