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XML Introspection and TreeView

By , 26 Jan 2009
 
IMG106.jpg

Introduction

I wrote this article to show how to associate data of TreeView and PropertyGrid.

Background 

I have described this on my blog but in French. (That's the reason why my English in not good.)

Using the Code 

You get data from XML (XmlDocument with XmlNodeCollection), and you use a TreeView (TreeView with TreeNode) to display them. 

When the user clicks on the TreeView, you want to display the XmlNode object in propertyGrid.

Then you have to associate the XmlNode with TreeNode, to display them for a propertyGrid, like that:  

propertyGrid1.SelectedObject = yourObject; 

The first and bad solution is to use Index or Name of TreeNode to find in XmlDocument, the XmlNode used to build the TreeNode.

So, you can try, but you'll be crazy, for example associate XmlNode and TreeNode in a List, or Array... something strange like that.

My solution might not be better, but I like it.

Derive the TreeNode, to an XmlNodeTree associated TreeNode and XmlNode.

 public class XmlNodeTree : TreeNode
        {
            private XmlNode mNode;
            public XmlNode Node
            {
                get { return mNode; }
            }

             public XmlNodeTree(XmlNode node)
            {
                mNode = node;
                if (node.NodeType == XmlNodeType.Text)
                {
                    Text = node.InnerText;
                }
                else
                {
                    Text = node.Name;
                }

                if (node.Attributes != null)
                {
                    foreach (XmlAttribute a in node.Attributes)
                    {
                        Text += " " + a.OuterXml;
                    }
                }
            }
        }	

And for filling the TreeView, it's really easy:

  private void FillTreeView(TreeNodeCollection c,XmlNodeList l)
        {
            if (l == null)
            {
                return;
            }

            foreach (XmlElement e in l)
            {
                XmlNodeTree n = new XmlNodeTree(e);
                c.Add(n);
                FillTreeView(n.Nodes, e.ChildNodes);
            }
        }

Call this method by:

 XmlNodeTree root = new XmlNodeTree(doc.LastChild);
 treeView1.Nodes.Add(root);
 FillTreeView(root.Nodes,doc.LastChild.ChildNodes);

Then when the user clicks on the TreeView:

XmlNodeTree currentNode = (XmlNodeTree) e.Node;
propertyGrid1.SelectedObject = currentNode.Node;

Points of Interest

So in one hundred lines of code, you have an XML viewer.  

You can modify it easily to make a real editor. I add a text widget to view the XML content.

History 

I tried to use FireBall editor to see XML in FireBall.CodeEditor with some problem, so I deliver the project to you without it.  

Please see other stuff here.

I will publish an XML introspector later to make this more complete.

Thanks to acton101 for helping to resolve a bug.

There's a problem in FillTreeView.
Replace foreach (XmlElement e in l) with foreach (XmlNode e in l).
This is because XmlText can't be cast to XmlElement.

Read the hierarchy of XmlText.

Added another test about the existence of XmlAttribute.

License

This article, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

About the Author

zebulon75018
Software Developer (Senior) http://www.cmb-soft.com/
France France
Member
No Biography provided

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GeneralMy vote of 5membermanoj kumar choubey26 Feb '12 - 21:12 
GeneralthanksmemberMember 41913661 Aug '09 - 0:35 
GeneralIt cannot open a valid XML file properlymemberacton10119 Jan '09 - 10:54 
GeneralRe: It cannot open a valid XML file properlymemberzebulon7501826 Jan '09 - 13:47 
GeneralRe: It cannot open a valid XML file properlymemberacton10127 Jan '09 - 5:15 

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