Some functions for calculating loans and car leases

Introduction

I know, this is probably not very exciting stuff, but may turn useful for some of you one day… Maybe for calculating your car / house repayments, or maybe writing a program that needs to calculate this.

The basis for this set of function is derived from the Microsoft Excel formula documentation on the subject and with lots of help of our own in house “Math teacher” (thanks Andrew) we managed to put this together for the benefit of the community and as our humble contribution to the forum.

Firstly – here is the Excel formula in its raw format

Now to some relevant terminology…

A “loan” is made up of several elements, each playing a different role in the equation. At times, you may need to know different things about the loan; therefore I provided here several functions.

OK – enough of that blurb… here are the actual functions:

double MKCalcPayment(int NumPay, double IntRate, double NPV, double FV, 
                     BOOL bStart)
{
    IntRate /= 1200.00;
    double P = (- NPV * pow(1+IntRate,NumPay) + FV) / 
               ((1 + IntRate * bStart)*((pow((1 + IntRate),NumPay) - 1) / 
               IntRate));
    return P * (-1); // Just convert it into a positive value.
}
 

double MKCalcInterest(double NumPay, double Payment, double NPV, double FV, 
                      BOOL bStart)
{
    // Start with an arbitrary 1% Interest rate
    double IntRate = 1.00 / 1200.00;
    NPV *= (-1);
    double iPer = log((Payment + Payment*IntRate*bStart - FV*IntRate) / 
                  (NPV*IntRate + Payment + Payment*IntRate*bStart) ) / 
                  log (1 + IntRate);
 
    if (iPer > NumPay)
    {
        while (iPer > NumPay)
        { 
            IntRate -= 0.000001;
            iPer = log((Payment + Payment*IntRate*bStart - FV*IntRate) / 
                       (NPV*IntRate + Payment + Payment*IntRate*bStart) ) / 
                   log (1 + IntRate);
        }
    }
    else
    {
        while (iPer < NumPay)
        {
            IntRate += 0.000001;
            iPer = log((Payment + Payment*IntRate*bStart - FV*IntRate) / 
                       (NPV*IntRate + Payment + Payment*IntRate*bStart) ) / 
                   log (1 + IntRate);
        }
    }
    return IntRate * 1200.00;
}
 

double MKCalcPeriods(double Payment, double IntRate, double NPV, double FV, 
                     BOOL bStart)
{
    IntRate /= 1200.00;
    NPV *= (-1);
    return log((Payment + Payment*IntRate*bStart - FV*IntRate) / 
               (NPV*IntRate + Payment + Payment*IntRate*bStart) ) / 
           log (1 + IntRate);
}

 
double MKCalcResidual(double Payment, int NumPay, double IntRate, double NPV, 
                      BOOL bStart)
{
    IntRate /= 1200.00;
    return -Payment * ((1 + IntRate * bStart)*((pow((1 + IntRate),NumPay) - 1) 
           / IntRate)) + (NPV * pow(1+IntRate,NumPay)); 

}

All of the above functions are arithmetic juggling of the original formula, with the exception of the one named MKCalcInterest which does a bit of “Guessing” as to what the Interest rate is for a set of given arguments. If you read the Excel on line help you will see that there is no direct way of finding the answer otherwise.

So now – lets look at some examples

1. I want a loan of $25,000 for a 5-year period with monthly repayments and an annual compound interest rate of 10% and ZERO residual at the end. Calling the MKCalcPayment function results in $531.18 per month.
2. If on the other end, I can afford to pay only $400.00 and on the same amount I wish to borrow (at the same interest rate) how long will it take me to repay this? Calling the MKCalcPeriods shows that we now have to pay 88.65 payments instead of 60…
3. Well now – what if I want to stay with the 60 instalments, but I can only afford that same $400.00 a month – there will obviously be some left over (residual) – calling the MKCalcResidual returns this to be equal to $10,157.89. Well it seems you cant have it all – you either pay more each month, or you pay for a longer period, or you are left out with something to pay at the end…
4. Finally, what if I want to find out – what will be the actual effective / compound annual interest rate on that same amount – if I borrow it for a 60 month period, pay $550.00 per month and call the MKCalcInterest function – the answer is 11.52% per annum… This means that you should be paying less than 60 installments – otherwise you are paying too much. See why by looking at the 1^st example.

Well, I am just about done, you can play with more examples – paying ahead or in arrears, with or without a residual etc..

Have fun

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