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First Posted 29 Apr 2003
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Windows Impersonation using C#

By | 29 Apr 2003 | Article
An article demonstrating how to use Windows impersonation in your C# code

Impersonation

Introduction

I've been a member of the CodeProject for over 3 years now, and still haven't contributed any articles - until now.

While designing a Windows Forms-based application, to administrate containers in our Active Directory, I needed a way to allow binding to the AD using alternate credentials. Windows impersonation was the answer. This sample app demonstrates how to use unmanaged code by calling LogonUser() contained within the advapi32.dll, and pass a token handle back to your .NET application using WindowsImpersonationContext.

One of the downfalls to the LogonUser()function is that the password get passed in clear-text.

Partial Source Code

using System.Runtime.InteropServices; // DllImport
using System.Security.Principal; // WindowsImpersonationContext
using System.Security.Permissions; // PermissionSetAttribute
...

public WindowsImpersonationContext 
    ImpersonateUser(string sUsername, string sDomain, string sPassword)
{
    // initialize tokens
    IntPtr pExistingTokenHandle = new IntPtr(0);
    IntPtr pDuplicateTokenHandle = new IntPtr(0);
    pExistingTokenHandle = IntPtr.Zero;
    pDuplicateTokenHandle = IntPtr.Zero;
    
    // if domain name was blank, assume local machine
    if (sDomain == "")
        sDomain = System.Environment.MachineName;

    try
    {
        string sResult = null;

        const int LOGON32_PROVIDER_DEFAULT = 0;

        // create token
        const int LOGON32_LOGON_INTERACTIVE = 2;
        //const int SecurityImpersonation = 2;

        // get handle to token
        bool bImpersonated = LogonUser(sUsername, sDomain, sPassword, 
            LOGON32_LOGON_INTERACTIVE, LOGON32_PROVIDER_DEFAULT, 
                ref pExistingTokenHandle);

        // did impersonation fail?
        if (false == bImpersonated)
        {
            int nErrorCode = Marshal.GetLastWin32Error();
            sResult = "LogonUser() failed with error code: " + 
                nErrorCode + "\r\n";

            // show the reason why LogonUser failed
            MessageBox.Show(this, sResult, "Error", 
                MessageBoxButtons.OK, MessageBoxIcon.Error);
        }

        // Get identity before impersonation
        sResult += "Before impersonation: " + 
            WindowsIdentity.GetCurrent().Name + "\r\n";

        bool bRetVal = DuplicateToken(pExistingTokenHandle, 
            (int)SECURITY_IMPERSONATION_LEVEL.SecurityImpersonation, 
                ref pDuplicateTokenHandle);

        // did DuplicateToken fail?
        if (false == bRetVal)
        {
            int nErrorCode = Marshal.GetLastWin32Error();
            // close existing handle
            CloseHandle(pExistingTokenHandle); 
            sResult += "DuplicateToken() failed with error code: " 
                + nErrorCode + "\r\n";

            // show the reason why DuplicateToken failed
            MessageBox.Show(this, sResult, "Error", 
                MessageBoxButtons.OK, MessageBoxIcon.Error);
            return null;
        }
        else
        {
            // create new identity using new primary token
            WindowsIdentity newId = new WindowsIdentity
                                        (pDuplicateTokenHandle);
            WindowsImpersonationContext impersonatedUser = 
                                        newId.Impersonate();

            // check the identity after impersonation
            sResult += "After impersonation: " + 
                WindowsIdentity.GetCurrent().Name + "\r\n";
            
            MessageBox.Show(this, sResult, "Success", 
                MessageBoxButtons.OK, MessageBoxIcon.Information);
            return impersonatedUser;
        }
    }
    catch (Exception ex)
    {
        throw ex;
    }
    finally
    {
        // close handle(s)
        if (pExistingTokenHandle != IntPtr.Zero)
            CloseHandle(pExistingTokenHandle);
        if (pDuplicateTokenHandle != IntPtr.Zero) 
            CloseHandle(pDuplicateTokenHandle);
    }
}

Points of Interest

This code won't work on Windows 98 or ME because they do not utilize user tokens. Code was built and run using Visual Studio.NET 2002 on Windows XP Service Pack 1.

One of the other uses for this code I've found is, for instantiating COM components that must run in an alternate security context to that of the logged-on user.

If anyone has a more secure method of achieving the same thing, please let me know.

History

  • Version 1.0 - 04.25.03 - First release version

License

This article has no explicit license attached to it but may contain usage terms in the article text or the download files themselves. If in doubt please contact the author via the discussion board below.

A list of licenses authors might use can be found here

About the Author

Marc Merritt

Technical Lead
Motorcycle Road Racing Forums
United States United States

Member

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I live in southeastern Pennsylvania, USA with my lovely wife and two beautiful daughters. Life is good. My hobbies are motorcycles, motorcycles, and motorcycles.

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Comments and Discussions

 
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GeneralRe: Coding Style Issues PinmemberMaximilian Hänel4:56 28 May '03  
GeneralJust to complete this PinmemberJahava4:53 25 Oct '03  
GeneralRe: Just to complete this PinmemberMarc Merritt8:42 25 Oct '03  
GeneralWhat an attitude... PinmemberJahava5:08 27 Oct '03  
GeneralRe: What an attitude... PinmemberMarc Merritt5:46 27 Oct '03  
GeneralIt's cool PinmemberJahava13:45 27 Oct '03  
GeneralRe: Coding Style Issues PinmemberJonathan C Dickinson1:53 5 May '08  
That form of try/catch usually helps with debugging...
GeneralError messages PinmemberMaximilian Hänel1:24 6 May '03  
GeneralRe: Error messages PinmemberHaidong Chen12:15 27 May '03  
GeneralRe: Error messages PinmemberHaidong Chen12:17 27 May '03  
GeneralRe: Error messages PinmemberMaximilian Hänel12:47 27 May '03  
GeneralSeImpersonatePrivilege Pinmembergeo_m22:56 3 May '03  
GeneralThis method won't work on Windows 2000 or Windows NT PinmemberSoftomatix13:54 3 May '03  
GeneralRe: This method won't work on Windows 2000 or Windows NT PinmemberMarc Merritt15:53 3 May '03  
GeneralRe: This method won't work on Windows 2000 or Windows NT PinmemberSoftomatix3:57 4 May '03  
GeneralRe: This method won't work on Windows 2000 or Windows NT PinsussDanko Greiner0:44 14 Dec '04  

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