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Fast regular expressions

By , 29 Oct 2000
 

Sample Image - RexSearch.jpg

Introduction

Regular expressions are a well recognized way for describing string patterns. The following regular expression defines a floating point number with a (possibly empty) integer part, a non empty fractional part and an optional exponent:

[0-9]* \.[0-9]+ ([Ee](\+|-)?[0-9]+)?

The rules for interpreting and constructing such regular expressions are explained below. A regular expression parser takes a regular expression and a source string as arguments and returns the source position of the first match. Regular expression parsers either interpret the search pattern at runtime or they compile the regular expression into an efficient internal form (known as deterministic finite automaton). The regular expression parser described here belongs to the second category. Besides being quite fast, it also supports dictionaries of regular expressions. With the definitions $Int= [0-9], $Frac= \.[0-9]+ and $Exp= ([Ee](\+|-)?[0-9]+), the above regular expression for a floating point number can be abbreviated to $Int* $Frac $Exp?.

Interface

I separated algorithmic from interface issues. The files RexAlgorithm.h and RexAlgorithm.cpp implement the regular expression parser using only standard C++ (relying on STL), whereas the file RexInterface.h and RexInterface.cpp contain the interfaces for the end user. Currently there is only one interface, implemented in the class REXI_Search. Interfaces for replace functionality and for programming language scanners are planned for future releases.

struct REXI_DefErr{
        enum{eNoErr,eErrInName,eErrInRegExp} eErrCode;
        string  strErrMsg;
        int     nErrOffset;
};
class REXI_Search : public REXI_Base
{ 
public:
    REXI_Search(char cEos='\0');

    REXI_DefErr
            AddRegDef   (string strName,string strRegExp);
    inline  REXI_DefErr  
            SetRegexp  (string strRegExp);
    bool    MatchHere   (const char*& rpcszSrc, int& nMatchLen,bool& bEos);
    bool    Find        (const char*& rpcszSrc, int& nMatchLen,bool& bEos);
private:
    bool    MatchHereImpl();
    int     m_nIdAnswer;
};

Example usage

int main(int argc, char* argv[])
{
    const char szTestSrc[]= "3.1415 is the same as 31415e-4";
    const int ncOk= REXI_DefErr::eNoErr;
    
    REXI_Search rexs; 
    REXI_DefErr err;
    err= rexs.AddRegDef("$Int","[0-9]+");  assert(err.eErrCode==ncOk);
    err= rexs.AddRegDef("$Frac","\\.[0-9]+"); assert(err.eErrCode==ncOk);
    err= rexs.AddRegDef("$Exp","([Ee](\\+|-)?[0-9]+)"); 
                                assert(err.eErrCode==ncOk);
    err= rexs.SetRegexp("($Int? $Frac $Exp?|$Int \\. $Exp?|$Int $Exp)[fFlL]?");
                                assert(err.eErrCode==ncOk);

    const char*     pCur= szTestSrc;
    int             nMatchLen;
    bool            bEosFound= false;
    cout    <<  "Source text is: \""    <<  szTestSrc   << "\"" <<  endl;
    while(rexs.Find(pCur,nMatchLen,bEosFound)){
           cout <<  "Floating point number found  at position "       
                <<  ((pCur-szTestSrc)-nMatchLen)    
                <<  " having length "  <<  nMatchLen  <<  endl;
    }
    int i;
    cin >> i;
    return 0;
}

Performance issues

A call to the member function REXI_Search::SetRegexp(strRegExp)involves quite a lot of computing. The regular expression strRegExp is analyzed and after several steps transformed into a compiled form. Because of this preprocessing work, which is not needed in the case of an interpreting regular expression parser, this regular expression parser shows its efficiency only when you apply it to large input strings or if you are searching again and again for the same regular expression. A typical application which profits from the preprocessing needed by this parser is a utility which searches all files in a directory.

Limitations

Currently Unicode is not supported. There is no fundamental reason for this limitation and I think that a later release will correct this. I just did not yet find an efficient representation of a compiled regular expression which supports Unicode.

Constructing regular expressions

Regular expressions can be built from characters and special symbols. There are some similarities between regular expressions and arithmetic expressions. The most basic elements of arithmetic expressions are numbers and expressions enclosed in parens ( ). The most basic elements of regular expressions are characters, regular expressions enclosed in parens ( ) and character sets. On the next higher level, arithmetic expressions have '*' and '/' operators, whereas regular expressions have operators indicating the multiplicity of the preceding element.

Most basic elements of regular expressions

  • Individual characters. e.g. "h" is a regular expression. In the string "this home" it matches the beginning of 'home'. For non printable characters, one has to use either the notation \xhh where h means a hexadecimal digit or one of the escape sequences \n \r \t \v known from "C". Because the characters * + ? . | [ ] ( ) - $ ^ have a special meaning in regular expressions, escape sequences must also be used to specify these characters literally: \*  \+  \?  \.  \|  \[  \]  \(  \)  \-  \$  \^ . Furthermore, use '\ ' to indicate a space, because this implementation skips spaces in order to support a more readable style.
  • Character sets enclosed in square brackets [ ]. e.g. "[A-Za-z_$]" matches any alphabetic character, the underscore and the dollar sign (the dash (-) indicates a range), e.g. [A-Za-z$_] matches "B", "b", "_", "$" and so on. A ^ immediately following the [ of a character set means 'form the inverse character set'. e.g. "[^0-9A-Za-z]" matches non-alphanumeric characters.
  • Expressions enclosed in round parens ( ). Any regular expression can be used on the lowest level by enclosing it in round brackets.
  • the dot . It means 'match any character'.
  • an identifier prefixed by a $. It refers to an already defined regular expression. e.g. "$Ident" stands for a user defined regular expression previously defined. Think of it as a regular expression enclosed in round parens, which has a name.

Operators indicating the multiplicity of the preceding element

Any of the above five basic regular expressions can be followed by one of the special characters * + ? /i

  • * meaning repetition (possibly zero times); e.g. "[0-9]*" not only matches "8" but also "87576" and even the empty string "".
  • + meaning at least one occurrence; e.g. "[0-9]+" matches "8", "9185278", but not the empty string.
  • ? meaning at most one occurrence; e.g. "[$_A-Z]?" matches "_", "U", "$", .. and ""
  • \i meaning ignore case

Catenation of regular expressions

The regular expressions described above can be catenated to form longer regular expressions. E.g. "[_A-Za-z][_A-Za-z0-9]*" is a regular expression which matches any identifier of the programming language "C", namely the first character must be alphabetic or an underscore and the following characters must be alphanumeric or an underscore. "[0-9]*\.[0-9]+" describes a floating point number with an arbitrary number of digits before the decimal point and at least one digit following the decimal point. (The decimal point must be preceded by a backslash, otherwise the dot would mean 'accept any character at this place'). "(Hallo (,how are you\?)?)\i" matches "Hallo" as well as "Hallo, how are you?" in a case insensitive way.

Alternative regular expressions

Finally - on the top level - regular expressions can be separated by the | character. The two regular expressions on the left and right side of the | are alternatives, meaning that either the left expression or the right expression should match the source text. E.g. "[0-9]+ | [A-Za-z_][A-Za-z_0-9]*" matches either an integer or a "C"-identifier.

A complex example

The programming language "C" defines a floating point constant in the following way: A floating point constant has the following parts: An integer part, a decimal point, a fraction, an exponential part beginning with e or E followed by an optional sign and digits and an optional type suffix formed by one the characters f, F, l, L. Either the integer part or the fractional part can be absent (but not both). Either the decimal point or the exponential part can be absent (but not both).

The corresponding regular expression is quite complex, but it can be simplified by using the following definitions:

$Int = "[0-9]+."
$Frac= "\.[0-9]+".
$Exp = "([Ee](\+|-)?[0-9]+)".

So we get the following expression for a floating point constant:

($Int? $Frac $Exp?|$Int \. $Exp?|$Int $Exp)[fFlL]?

License

This article has no explicit license attached to it but may contain usage terms in the article text or the download files themselves. If in doubt please contact the author via the discussion board below.

A list of licenses authors might use can be found here

About the Author

Martin Holzherr
Switzerland Switzerland
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Comments and Discussions

 
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GeneralRe: that serious error in concatenating states corrected?memberMartin.Holzherr20 Mar '11 - 21:50 
Sorry, I did not work anymore on this. But, as far as I remember, the incorrect state concatenation shouldn't be difficult to fix.
GeneralDev c++memberf_randy4 Jun '06 - 11:11 
I am not able to compile this thing in Dev C++ Frown | :(
Generalplease help me!!!!sussfowadkhan8 Feb '05 - 22:45 
1.construct a program for regular language
such that
submission=[ a b c 1 2 3 ]
operator=[ + * |]
 
2.construct a regular expression
3.excecute the domain; such that domain length =100 words
length word=5 to 10 char
4. use regular expression keys given in operator domain
5. collect the selected words in file

GeneralHelp Neededsussnoogui29 Oct '04 - 10:36 
Can anyeone tell me how can what is the regular expression for integers in C Programming language ( including octal ,decimal and hexadecimal values regardless of the boundaries in C for the int )
 
Also what is the regular expression for the float ?
 
And how can we turn it into NFA or DFA ?
 

GeneralBugsmemberlucky_by2 Jun '04 - 2:19 
Nice article.
 
However I have found the following bugs in the examples:
 
transforming hex digits to char
RexAlgorithm.cpp line 344:
< hexChar+= isdigit(rpFrom[i])?(rpFrom[i]-'0')toupper(rpFrom[i])-'A'+16);
> hexChar+= isdigit(rpFrom[i])?(rpFrom[i]-'0')toupper(rpFrom[i])-'A'+10);
 
signed/unsigned issue:
RexAlgorithm.cpp line 299:
 
< const char* pCur= m_pTokEnd;
< while(isspace(*pCur))
< pCur++;
< return pCur;
 
> unsigned const char* pCur= (unsigned const char*)m_pTokEnd;
> while(isspace(*pCur))
> pCur++;
> return (const char*)pCur;
 
struct REXA_NDFATransition::m_bIsMute is used uninitialized (What this member is really intended for?)
 
And finally concatenation of 2 NFAs (REXA_ParserImpl::Concat) is wrong.
For example: a*b* will never match empty chain, and a*b*c will never match single "c"
 
Regards, Al (Lucky)

QuestionIs this gift Unicode-aware?memberRocom15 May '04 - 23:24 
Who can help me to improve this to support Unicode?
I look forward ...
 
hjsoft@sohu.com
 
Rocom Omen
GeneralExample doesn't find single filesmemberJon11 Nov '03 - 5:24 
Looks like a small bug in FindInThisDirectory().
 
I changed the loop to:
bool bWorking = true;
while (bWorking){
bWorking = findFile.FindNextFile();
 
and then it picked up the single file in the directory ok.
I think it's because FindNextFile returns zero on the last found occurance.
 
Jon

GeneralRe: Example doesn't find single filesmemberRocom15 May '04 - 19:24 
I also have found the bug. In FileFindRecursive.h, I change
the function like below:
void FindInThisDirectory(CString strDir)
{
CFileFind findFile;
BOOL bWorking = findFile.FindFile(strDir+"\\"+m_strWildCard);
while(bWorking){
bWorking = findFile.FindNextFile();
if( !findFile.IsDirectory() ){
m_bCanceled= !m_pFuncProcessFile(findFile.GetFilePath(),
findFile.GetFileName(),m_pData);
if( m_bCanceled )
return;
}
}

Recurse(strDir);
}
GeneralBug in REXA_Scanner::operator()()sussJerome Herry28 Aug '03 - 3:27 
Hi all,
 
I found a bug in the function REXA_ESymbols REXA_Scanner::operator()()
When looking for a rule identifier this test is performed:
 
while( isalpha(*m_pTokEnd) || isdigit(*m_pTokEnd) || m_pTokEnd[1]=='_' )
{
m_strLiteral+= *m_pTokEnd++;
}
 
It must be
 
while( isalpha(*m_pTokEnd) || isdigit(*m_pTokEnd) || *m_pTokEnd=='_' )
{
m_strLiteral += *m_pTokEnd++;
}
 
Exemple:
Let's say that you have a rule named "$r01"
If you look for this pattern "$r01 __FILE__" you will have an error because it will look for the rule "$r01 " which does not exist (because of the space)
 

Jerome.

GeneralAlgorithmsussnachiappan12 Aug '03 - 8:01 
Good day!can u plz give me the algorithm for ur fast regular expression project.
 
nach
GeneralRe: AlgorithmmemberMartin Holzherr12 Aug '03 - 20:34 
Hi,
am I right, that you are
interested in the algorithm, not the code.

If so, I can give you a detailed description
in the next days (the exact description is
taken from a book on theoretical computer science).
The basic theory lying behind the code is
the transformation from a nondeterministic to
a deterministic finite machine.
A nondeterministic machine is easy to understand
and implement, because it is nothing more than
a set of nodes (in a graph) which go - at each node -
to the neighbouring node reachable by reading one of the next characters.
A nondeterministic machine - as the name implies - does not
give you a unique path, but - normally - at each step (reading the next character)
you can go decide to go one of many possible branches. But a wrong decision
can force you to backtrack - meaning that you must undo a decision and go back
to a previous state.
This means in the very end, that nonderministic machines are inefficient (but many
implementations use them).
The good news is, that the transformation is not difficult if you use sets
( I used std::set).
Furthermore this implementation gains much of its speed by using a
very simple and fast - but also space consuming - representation.
More about the algorithm in the next days.
Regards Martin

GeneralRe: Algorithmsussnachiap19 Aug '03 - 5:32 
thanks for ur reply,kindly post ur algorithm as soon as possible
GeneralRe: AlgorithmmemberCuick27 Aug '03 - 20:39 
Hi!
Can u send me the detailed description??
Thanks!
GeneralRe: AlgorithmmemberAmer Gerzic12 Nov '03 - 12:46 
Maybe this will help:
http://www.codeproject.com/useritems/OwnRegExpressionsParser.asp
 
I am not sure though if the algorithm is the same, but this one should be very fast!
 
Amer
GeneralRe: AlgorithmmemberRocom15 May '04 - 18:55 
I'm eager for your detailed description, too.
Thanks, your code are nice for a certainty!
 
My E-Mail:hjsoft@sohu.com
 
Rocom Omen
GeneralProblem with some characters on UNIXsussJerome Herry28 Jul '03 - 21:56 
Hi,
 
I just want to tell you about this problem I met on SUN Solaris with gcc 2.95. Spaces are skiped with the "isspace" function which seems to also skip some other characters like "Ã" (\195). Maybe you should only compare to the ' ' character...
 
Regards,
Jerome.
GeneralValidating Datemembergrscot31 Dec '02 - 4:42 
Hi
I would like to validate a date in the format:mm dd yyyy in C++.
I have no idea of regular expressions. Could someone help me?
The date is entered as a string.
 
Regards,
Chris
 

GeneralQuick questionmemberHockey20 Oct '02 - 11:10 
Regular expression parsers either interpret the search pattern at runtime or they compile the regular expression into an efficient internal form (known as deterministic finite automaton). The regular expression parser described here belongs to the second category
 
Does this mean I can change the string i've fed the regex and assume the expression will not have to be re-evaluated...?
 
I have a buffer which is updated every second or so and I must strip HTML tags each time.
 

Cheers!
 
"An expert is someone who has made all the mistakes in his or her field" - Niels Bohr
GeneralRe: Quick questionmemberMartin Holzherr12 Aug '03 - 20:43 
The regular expression has to be evaluated each
time you change it. But you can use the same expression
for an unlimited number of input files.
 
If you only have a few expressions, you can
use more than one instance of the regular expression
class.
Regards Martin
 

GeneralBackreferencesmembermst7 Aug '02 - 0:20 
Hi there!
 
I want to find strings like
A123A
B123B
but not
A123B
using the expression \([A-Z]\)[1-9]+\1 which uses so called backreferences (works in TextPad, a real cool editor).
I Wonder if REXI_Search is able to process expressions like that?

 
regards
mst
GeneralBug or Feature using '*' and '+'membermst5 Aug '02 - 5:01 
Hi there!
 
First of all: REXI_Search is great and realy fast! Thanx a lot.
 
One problem left:
Whenever I use an expression like "ABC.*XYZ" on a text like
 

ABCIIIIIIXYZIIIIABCIIIIIXYZIIII
^-------------------------^

the occurance found is the on marked above. In my opinion it should be
 

ABCIIIIIIXYZIIIIXYZIIIIIXYZIIII
^----------^

isn't it?
 
regards
Markus
 

GeneralRe: Bug or Feature using '*' and '+'memberMartin Holzherr5 Aug '02 - 5:42 
Hi Markus,
there are different solutions to your matching problem.
REXI_Search always searches for the longest possible match not just for the first found. In most cases this is the behavour wanted,
e.g. if you use a regular expression parser for scanning the tokens of a programming language, then this is just what you expect.
To search for a C-like identifier you can use the following expression
[_A-Za-z][_A-Za-z0-9]*
to match identifiers like
totalTaxValue nofDigits _myHiddenVariable
 
Regards Martin

GeneralRe: Bug or Feature using '*' and '+'memberCodebender17 Dec '04 - 13:11 
'*' is greedy by default. What you want is '.*?', which is the non-greedy version of '*'. That is, it matches as few characters as possible. Unfortunately, this RegEx processor does not appear to support non-greedy matching.
Generalcompiled versionmemberJanie624 Jul '02 - 12:52 
Could someone send me the compiled version of this application. It looks pretty useful, but I am unable to compile it using VC 5++
 
If you wish to send the application, you can email it to
umjaco6@hotmail.com
 
Thanks
JanieRose | [Rose]
Generalcan't compile in VC++ 5sussAnonymous10 Jul '02 - 8:29 
Is this project supposed to be able to compile in Visual C++ 5.0?
 
I can't seem to get it working.

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