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License: The Code Project Open License (CPOL)
Simple slide game using ViewboxBy Sacha BarberA simple 9 peice puzzle using ImageBrush.ViewBox |
C# (C# 3.0), .NET (.NET 3.5), WPF, Architect, Dev, Design
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This is a very simple article that really just demonstrates the various capabilities
of the WPF ImageBrush. The basic idea is that the attached demo
emulated one of those 9 square puzzles you used to get in XMAS stockings.
Where 1 square was blank, and the image portions in the other 8 squares were randomly scattered, and you had to try and recreate the whole image, by sliding the image portion squares into the blank space, and repeating this until you had the whole image again.
In a nutshell thats all this article does.
Well its based in WPF land, so we can use a convienient layout manager called
a Grid which has Rows/Columns. So we can imagine that each Row/Column
of the Grid will either hold a square which holds a section of
the original image, or will be the single blank square.
And that's exactly what we do.
The basic steps are as follows:
Thats all there is to it.
So let's look at each of these steps in a bit more detail
Loading an image is done by the button click event that allows the user to grab a new image, the code is as follows:
Microsoft.Win32.OpenFileDialog ofd = new Microsoft.Win32.OpenFileDialog();
ofd.Filter = "Image Files(*.BMP;*.JPG;*.GIF;*.PNG)|*.BMP;*.JPG;*.GIF;*.PNG" +
"|All Files (*.*)|*.*";
ofd.Multiselect = false;
if (ofd.ShowDialog() == true)
{
try
{
image = new BitmapImage(new Uri(ofd.FileName, UriKind.RelativeOrAbsolute));
img = new Image { Source = image };
CreatePuzzleForImage();
}
catch
{
MessageBox.Show("Couldnt load the image file " + ofd.FileName);
}
}
We need to grab sequential portions of the original image, but only grab 8, as we need the 9th square to be a blank. So this is done using the following code:
//row0
CreateImagePart(0, 0, 0.33333, 0.33333);
CreateImagePart(0.33333, 0, 0.33333, 0.33333);
CreateImagePart(0.66666, 0, 0.33333, 0.33333);
//row1
CreateImagePart(0, 0.33333, 0.33333, 0.33333);
CreateImagePart(0.33333, 0.33333, 0.33333, 0.33333);
CreateImagePart(0.66666, 0.33333, 0.33333, 0.33333);
//row2
CreateImagePart(0, 0.66666, 0.33333, 0.33333);
CreateImagePart(0.33333, 0.66666, 0.33333, 0.33333);
Where the CreateImagePart() method looks like the following:
private void CreateImagePart(double x, double y, double width, double height)
{
ImageBrush ib = new ImageBrush();
ib.Stretch = Stretch.UniformToFill;
ib.ImageSource = image;
ib.Viewport = new Rect(0, 0, 1.0, 1.0);
//grab image portion
ib.Viewbox = new Rect(x, y, width, height);
ib.ViewboxUnits = BrushMappingMode.RelativeToBoundingBox;
ib.TileMode = TileMode.None;
Rectangle rectPart = new Rectangle();
rectPart.Fill = ib;
rectPart.Margin = new Thickness(0);
rectPart.HorizontalAlignment = HorizontalAlignment.Stretch;
rectPart.VerticalAlignment = VerticalAlignment.Stretch;
rectPart.MouseDown += new MouseButtonEventHandler(rectPart_MouseDown);
initialUnallocatedParts.Add(rectPart);
}
The most important parts of this is the line that sets the ImageBrush
ViewPort, ib.Viewport = new Rect(0, 0, 1.0, 1.0). This means
start at 0,0 and end at the end of the image. In WPF 0,0 means top left, which
1.0,1.0 means bottom right.
The other important part is where we grab the ImageBrush Viewbox,
which is where we grab only the portion of the image we want for the ImageBrush.
This simply uses the input parameters to grab the relevant section of the original
image. Neat I think.
Now it wouldn't be much of a puzzle if we laid the squares out in the order
that they were obtained, so we need to shake things up a bit. We need some randomness.
This is achieved by the following method, where we randomly grab the 8 sequentially
obtained unallocated image portions and allocate them to a allocated List<Rectangle>
private void RandomizeTiles()
{
Random rand = new Random();
int allocated = 0;
while (allocated != 8)
{
int index = 0;
if (initialUnallocatedParts.Count > 1)
{
index = (int)(rand.NextDouble() * initialUnallocatedParts.Count);
}
allocatedParts.Add(initialUnallocatedParts[index]);
initialUnallocatedParts.RemoveAt(index);
allocated++;
}
}
We then need to fill the Grid with these random image portions
and a single blank Rectangle which was added to the end of the
allocated List<Rectangle>.
int index = 0;
for (int i = 0; i < 3; i++)
{
for (int j = 0; j < 3; j++)
{
allocatedParts[index].SetValue(Grid.RowProperty, i);
allocatedParts[index].SetValue(Grid.ColumnProperty, j);
gridMain.Children.Add(allocatedParts[index]);
index++;
}
}
As we cunningly used Rectangle objects to put into the Grid,
we are able to use RoutedEvents. This is because Rectangle
is a full blown WPF element, so has routed events. We simply hook into the MouseDown
RoutedEvent for each Rectangle. And then see if the Rectangle
clicked is allowed to be swapped with the current Blank Rectangle.
If it can be swapped, the 2 Rectangles are swapped (reallocated
to different Grid Row/Column).
This is done as follows:
private void rectPart_MouseDown(object sender, MouseButtonEventArgs e)
{
//get the source Rectangle, and the blank Rectangle
//NOTE : Blank Rectangle never moves, its always the last Rectangle
//in the allocatedParts List, but it gets re-allocated to
//different Gri Row/Column
Rectangle rectCurrent = sender as Rectangle;
Rectangle rectBlank = allocatedParts[allocatedParts.Count - 1];
//get current grid row/col for clicked Rectangle and Blank one
int currentTileRow = (int)rectCurrent.GetValue(Grid.RowProperty);
int currentTileCol = (int)rectCurrent.GetValue(Grid.ColumnProperty);
int currentBlankRow = (int)rectBlank.GetValue(Grid.RowProperty);
int currentBlankCol = (int)rectBlank.GetValue(Grid.ColumnProperty);
//create possible valid move positions
List<PossiblePositions> posibilities = new List<PossiblePositions>();
posibilities.Add(new PossiblePositions
{ Row = currentBlankRow - 1, Col = currentBlankCol });
posibilities.Add(new PossiblePositions
{ Row = currentBlankRow + 1, Col = currentBlankCol });
posibilities.Add(new PossiblePositions
{ Row = currentBlankRow, Col = currentBlankCol-1 });
posibilities.Add(new PossiblePositions
{ Row = currentBlankRow, Col = currentBlankCol + 1 });
//check for valid move
bool validMove = false;
foreach (PossiblePositions position in posibilities)
if (currentTileRow == position.Row && currentTileCol == position.Col)
validMove = true;
//only allow valid move
if (validMove)
{
rectCurrent.SetValue(Grid.RowProperty, currentBlankRow);
rectCurrent.SetValue(Grid.ColumnProperty, currentBlankCol);
rectBlank.SetValue(Grid.RowProperty, currentTileRow);
rectBlank.SetValue(Grid.ColumnProperty, currentTileCol);
}
else
return;
}
And that's it. Really simply, as I said in the intro, but you never know you
may have just learnt a bit about the WPF ImageBrush. If you have
ever seen the Blendables zoom box this is based on the ImageBrush
concepts covered in this article.
Anyway why not try your luck. Have a go.
Though I must say I have not been able to complete 1 puzzle at all as yet. I never was much good at these damn puzzles. Grrrrr
v1.0 25/04/08
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Last Updated: 9 Aug 2008 Editor: |
Copyright 2008 by Sacha Barber Everything else Copyright © CodeProject, 1999-2009 Web17 | Advertise on the Code Project |