There are many situations when a user wants to allow a user to upload more than one file, you're stuck with either adding as many file input elements as the number of files you want to upload, or possibly having new ones appear 'magically' through Javascript.
This article helps in uploading multiple files simultaneously in ASP.Net . This article uses HTML File Input Control and Grid View.
Using this article doesn't get much simpler. Thanks to Microsoft's DotNet.
The heart of this article is the script which helps to get the FileOpen Dialog in ASP.Net
<script type="text/javascript" language="javascript"> function getFile() { document.getElementById("file1").click(); var file = ""; if(document.getElementById("TextBox1").value == "") file = document.getElementById("file1").value; else file = document.getElementById("TextBox1").value + "\r\n" + document.getElementById("file1").value; document.getElementById("TextBox1").value = file ; } </script>
To use this article. just run the web application, once done its easy just click the Add Files Button to start uploading the files the file along with the details is shown in the Grid View.
The Code for the Add Files Button Click is shown below :
protected void Button1_Click(object sender, EventArgs e) { if (TextBox1.Text.Length > 0) { DataTable dt; DataRow dr = null; FileInfo fileObj = new FileInfo(TextBox1.Text.Trim()); long size = fileObj.Length / 1024; loggedUser = "Administrator"; folderPath = System.Web.Hosting.HostingEnvironment.MapPath("~/" + loggedUser); System.IO.DirectoryInfo dirObj = new DirectoryInfo(folderPath); if (!dirObj.Exists) dirObj.Create(); try { fileObj.CopyTo(folderPath + "\\" + fileObj.Name); } catch (Exception ee) { TextBox1.Text = ""; string error = ee.Message.ToString(); Response.Write("<script> window.alert(' File With the same name already uploaded ')</script>"); return; } if (GridView1.Rows.Count == 0) { dt = new DataTable(); DataColumn dc1 = new DataColumn("File Name", typeof(string)); DataColumn dc2 = new DataColumn("File Size", typeof(string)); dt.Columns.Add(dc1); dt.Columns.Add(dc2); dr = dt.NewRow(); dr["File Name"] = TextBox1.Text.ToString().Trim(); if (size > 0) dr["File Size"] = size.ToString() + " KB"; else dr["File Size"] = fileObj.Length.ToString() + " Bytes"; dt.Rows.Add(dr); GridView1.DataSource = dt; GridView1.DataBind(); } else { int count = GridView1.Rows.Count; dt = new DataTable(); DataColumn dc1 = new DataColumn("File Name", typeof(string)); DataColumn dc2 = new DataColumn("File Size", typeof(string)); dt.Columns.Add(dc1); dt.Columns.Add(dc2); for (int i = 0; i < count; i++) { dr = dt.NewRow(); dr["File Name"] = GridView1.Rows[i].Cells[1].Text; dr["File Size"] = GridView1.Rows[i].Cells[2].Text; dt.Rows.Add(dr); } dr = dt.NewRow(); dr["File Name"] = TextBox1.Text.ToString().Trim(); if(size > 0) dr["File Size"] = size.ToString() + " KB"; else dr["File Size"] = fileObj.Length.ToString() + " Bytes"; dt.Rows.Add(dr); GridView1.DataSource = dt; GridView1.DataBind(); } TextBox1.Text = ""; } }
if u wish to delete the file then just use the delete option in the Grid View.
Once all the files to be uploaded are added u can continue processing the files and Upload the files by clicking the Upload Files Button. The processing code for Upload Files Button is left to the user.
This Article makes use of HTMLFile Input Control and Grid View. Its very simple and easy to work around.
Good Luck Guys.
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