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General Programming » Algorithms & Recipes » Computational Geometry     Intermediate License: The Code Project Open License (CPOL)

Bezier Curves Made Simple

By Tolga Birdal

A simple implementation of the famous Bezier curves in C#. Easy to understand.
C#, Windows, .NET, Dev
Posted:14 Apr 2008
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13 votes for this article.
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BezierInterpolation.gif

Introduction

Bezier curves are the most fundamental curves, used generally in computer graphics and image processing. These curves are mainly used in interpolation, approximation, curve fitting, and object representation. In this article, I will demonstrate, in a very simple and straightforward way, how one can construct these curves and make use of them.

Background

Bezier curves are parametric curves which are pretty much customizable and smooth. They are well suited for many applications. They were named after Pierre Bézier, a French mathematician and engineer who developed this method of computer drawing in the late 1960s while working for the car manufacturer Renault. People say that at the same time the same development took place during the research of Ford. There is still a confusion about who found it first.

Because of my imaging background, my article will mainly focus on interpolation and curve fitting. In interpolation, what one would simply like to do is to find unknown points using known values. This way, a discrete case can be represented with a more continuous structure, and we can have a well defined curve for missing points. The curve is initialized with certain data points, and it tries to generate new ones that are approximating (or interpolating) the old values.

Constructive Bezier Curve Algorithm

Consider the n+1 points P0,…,Pn and connect the points into a polyline we will denote hereafter as the control polygon.

figure2.jpg

Given points Pi, i = 0,...,n, our goal is to determine a curve g (t), for all values t Î [0,1]. The idea is demonstrated below:

figure.jpg

Basic Algorithm

The objective here is to find points in the middle of two nearby points and iterate this until we have no more iterations. The new values of points will give us the curve. The famous Bezier equation is the exact formulation of this idea. Here is the algorithm:

Step 1: Select a value t Î [0,1]. This value remains constant for the rest of the steps.

Step 2: Set Pi[0] (t) = Pi, for i = 0,...,n.

Step 3: For j= 0,...,n, set simple.jpg for i = j,...,n.

Step 4: g (t) = Pn[n] (t)

Special & General Cases

Now, I will give formulas for common, special cases that can be helpful in certain applications. The code of the article does not demonstrate any of them, but it uses the generalized formula. So, let me start with the generalized formula:

general.jpg

For the sake of simplicity and convention used in this article and code, it is better to represent this formula as:

notation.jpg

What this equation tells us is nothing but the formulation of the above algorithm (the mid-point iterations). It is very important in the sense that a whole algorithm could be summarized into a formula and a straightforward implementation would yield correct results. Here, n denotes the number of points and P denotes the points themselves. The factorial coefficients of the points are simply called the Bernstein basis functions, because of the name of the founder.

Here are the special cases:

Linear Bezier:

f1.jpg

Quadratic Bezier:

f3.jpg

Cubic Bezier:

f2.jpg

Understanding and Using the Code

This is the function, doing all the work. I think it is very short and very easy. Because we are dealing only with 2D curves, we have points in X and Y coordinates. The function simply calculates the Bezier points.

public void Bezier2D(double[] b, int cpts, double[] p)
{
    int npts = (b.Length) / 2;
    int icount, jcount;
    double step, t;

    // Calculate points on curve

    icount = 0;
    t = 0;
    step = (double)1.0 / (cpts - 1);

    for (int i1 = 0; i1 != cpts; i1++)
    { 
        if ((1.0 - t) < 5e-6) 
            t = 1.0;

        jcount = 0;
        p[icount] = 0.0;
        p[icount + 1] = 0.0;
        for (int i = 0; i != npts; i++)
        {
            double basis = Bernstein(npts - 1, i, t);
            p[icount] += basis * b[jcount];
            p[icount + 1] += basis * b[jcount + 1];
            jcount = jcount +2;
        }

        icount += 2;
        t += step;
    }
}

The rest of the functions are only helper functions taking part in factorial calculations and basis function calculations, which I believe are pretty obvious. To properly use this function, give it a set of points in the format: XYXYXYXYXYXYXYXYXYXY.... coordinates and how many points you would like to calculate on the curve. The function will fill the p array with the path points.

Points of Interest

Because of the limitations of factorial calculations, the code could only calculates curves up to 32 points. More complicated structures are generally represented by a combination of these curves (as in Adobe Photoshop, Illustrator, and Flash - path tool).

Even though GDI has a built-in Bezier curve calculation function, it is never good for learning to use built-in libraries. You won't always have GDI to do things for you! At some place, some time, you may have to implement it, and I think by now, you should have a rough idea of how these curves work.

License

This article, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

About the Author

Tolga Birdal


Member
A .NET and ASM C/C++ developer from Turkey who works on Computer Vision & Chief Engineer in BeFunky. Currently an MSc. student in Technical University of Munich.

I develop real life application in computer vision for almost 5 years. Currently interested in developing algorithms in C relating math and vision.

I admire performance in algorithms.

"Great minds never die, they just tend to infinity..."
Occupation: Chief Technology Officer
Company: BeFunky
Location: Turkey Turkey

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 Msgs 1 to 13 of 13 (Total in Forum: 13) (Refresh)FirstPrevNext
GeneralThanks! PinmemberGrummel9:09 24 Apr '08  
GeneralRe: Thanks! PinmemberTolga Birdal10:02 24 Apr '08  
GeneralRe: Thanks! PinmemberGrommel7:05 27 Apr '08  
GeneralRe: Thanks! PinmemberTolga Birdal8:40 27 Apr '08  
GeneralRe: Thanks! PinmemberGrommel4:04 28 Apr '08  
GeneralI think you have an understanding gap PinmemberFresric Bouemont0:47 15 Apr '08  
GeneralRe: I think you have an understanding gap PinmemberTolga Birdal3:27 15 Apr '08  
GeneralRe: I think you have an understanding gap PinmemberFresric Bouemont0:57 16 Apr '08  
GeneralRe: I think you have an understanding gap PinmemberTolga Birdal5:04 16 Apr '08  
GeneralRe: I think you have an understanding gap PinmemberFresric Bouemont8:52 16 Apr '08  
GeneralRe: I think you have an understanding gap PinmemberTolga Birdal10:26 16 Apr '08  
GeneralRe: I think you have an understanding gap PinmemberFresric Bouemont12:12 16 Apr '08  
GeneralRe: I think you have an understanding gap PinmemberTolga Birdal10:35 16 Apr '08  

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