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 | Putting it all together so far
murray56 | 17:15 2 Mar '07 |
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Hi,
Thanks so much for this nifty script. Putting all the suggestions together and changing s/p to x (s/p conflicts with the other options so I just picked x since it was free - is there another commonly used one?)
<script type="text/javascript">
var gsMonthNames = new Array(
'January',
'February',
'March',
'April',
'May',
'June',
'July',
'August',
'September',
'October',
'November',
'December'
);
var gsDayNames = new Array(
'Sunday',
'Monday',
'Tuesday',
'Wednesday',
'Thursday',
'Friday',
'Saturday'
);
String.prototype.zf = function(l) { return '0'.string(l - this.length) + this; }
String.prototype.string = function(l) { var s = '', i = 0; while (i++ < l) { s += this; } return s; }
Number.prototype.zf = function(l) { return this.toString().zf(l); }
// the date format prototype
Date.prototype.format = function(f)
{
if (!this.valueOf())
return 'n.a.';//
var d = this;
return f.replace(/(yyyy|yy|y|MMMM|MMM|MM|M|dddd|ddd|dd|d|HH|H|hh|h|mm|m|ss|s|t|x)/gi,
function($1)
{
switch ($1)
{
case 'yyyy': return d.getFullYear();
case 'yy': return (d.getFullYear()%100).zf(2);
case 'y': return (d.getFullYear()%100);
case 'MMMM': return gsMonthNames[d.getMonth()];
case 'MMM': return gsMonthNames[d.getMonth()].substr(0, 3);
case 'MM': return (d.getMonth() + 1).zf(2);
case 'M': return (d.getMonth() + 1);
case 'dddd': return gsDayNames[d.getDay()];
case 'ddd': return gsDayNames[d.getDay()].substr(0, 3);
case 'dd': return d.getDate().zf(2);
case 'd': return d.getDate();
case 'HH': return d.getHours().zf(2);
case 'H': return d.getHours();
case 'hh': return ((h = d.getHours() % 12) ? h : 12).zf(2);
case 'h': return ((h = d.getHours() % 12) ? h : 12);
case 'mm': return d.getMinutes().zf(2);
case 'm': return d.getMinutes();
case 'ss': return d.getSeconds().zf(2);
case 's': return d.getSeconds();
case 't': return d.getHours() < 12 ? 'am' : 'pm';
case 'x': var i = d.getDate() % 10; return 'thstndrd'.substr(2 * (i < 4) * i, 2);
}
}
);
}
</script>
Murray
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Whoops, I left the wrong bit in from my testing:
case 'x': var i = d.getDate() % 10; return 'thstndrd'.substr(2 * (i < 4) * i, 2);
should be:
case 'x':
switch (d.getDate())
{
case 1:
case 21:
case 31:
return "st";
case 2:
case 22:
return "nd";
case 3:
case 23:
return "rd";
default:
return "th";
}
Sorry 'bout dat
Murray
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Another commonly used date parts would be the time zone specifier (GMT, CMT, etc.) and the '07 year format. Please note that the 'x' case may yield 12nd for 12. Be careful with that, try another approach for ordinals...
There is no spoon.
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I am using:
case 'x':
switch (d.getDate())
{
case 1:
case 21:
case 31:
return "st";
case 2:
case 22:
return "nd";
case 3:
case 23:
return "rd";
default:
return "th";
}
which seems to work properly for all the numbers I have tested (including 12).
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| hey
Frenaaa | 9:09 3 Dec '06 |
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Jai! ai am javin som trobel loguin in to mai jotmeil acaunt. it sims dat mai pasbuord is not ricognaisd, iven doug ai meid shur dat ol de lirel lait bulbs on mai kibord ar torned on (including the guan coled caps loc)
ai guonder if llu can jelp mi bicos llu jav writen so meni artikels so ai gues llu jav jotmeil tu....
it guas very jard tu faind llu, BUT I DID SO I AM F***ING AWESOME!!! THE MINE SO BIG SO THE MINE SO FINE SO TOR2K QUE ARRECHO EL CD QUE ME MANDASTE!!! DIOS TE BENDIGA HIJO MIOOOOOOOOO! SO BIGGGGGGG!!! D.A.R.E. JAJAJAJA A3VT! LOVIN YA INZA! U CAN RUN BUT YOU CANT HIDE! JAJAJA,
there is no spoon.
PD. FREEEEENAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA!!!
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what up d mine!!!! hacker mardito... me alegro q t gustara el CD... disfrutenlo! i love u 2!
Try not to bend the spoon, that's impossible; instead try to realize the truth: There is no spoon.
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| Easy but useful
Ninghuan | 23:01 25 Apr '06 |
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| C#-like formats
Kjetil Klaussen | 0:15 9 Mar '06 |
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Great article, though it would be nice if you added the Zero-Fill functions to your article and not only in the comments 
Anyway; just a little update if you'd like to use C#-like formating;
return f.replace(/(yyyy|yy|y|MMMM|MMM|MM|M|dddd|ddd|dd|d|HH|H|hh|h|mm|m|ss|s|t)/gi,
function($1)
{
switch ($1)
{
case 'yyyy': return d.getFullYear();
case 'yy': return (d.getFullYear()%100).zf(2);
case 'y': return (d.getFullYear()%100);
case 'MMMM': return gsMonthNames[d.getMonth()];
case 'MMM': return gsMonthNames[d.getMonth()].substr(0, 3);
case 'MM': return (d.getMonth() + 1).zf(2);
case 'M': return (d.getMonth() + 1);
case 'dddd': return gsDayNames[d.getDay()];
case 'ddd': return gsDayNames[d.getDay()].substr(0, 3);
case 'dd': return d.getDate().zf(2);
case 'd': return d.getDate();
case 'HH': return d.getHours().zf(2);
case 'H': return d.getHours();
case 'hh': return ((h = d.getHours() % 12) ? h : 12).zf(2);
case 'h': return ((h = d.getHours() % 12) ? h : 12);
case 'mm': return d.getMinutes().zf(2);
case 'm': return d.getMinutes();
case 'ss': return d.getSeconds().zf(2);
case 's': return d.getSeconds();
case 't': return d.getHours() < 12 ? 'A.M.' : 'P.M.';
}
}
);
-------------------
Kjetil Klaussen
-------------------
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| ZF
Tunez | 2:09 1 Aug '05 |
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The prototype of 'zf' would be appriciated
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Ok, here it goes:
String.prototype.zf = function(l) { return '0'.string(l - this.length) + this; }
As you can see, it depends on the string prototype, an VB-like string concatenator:
String.prototype.string = function(l) { var s = '', i = 0; while (i++ < l) { s += this; } return s; }
Just bear in mind there's no check for the l (length) parameter, so you must always provide a number, and finally, you must create a number prototype for it (kind of an override) in order to use it directly on numbers:
Number.prototype.zf = function(l) { return this.toString().zf(l); }
I hope this helps.
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| A couple of bugs
Richard Deeming | 8:08 26 Jul '05 |
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Since you're using a case-insensitive regular expression, you should ensure that the switch statement is also case-insensitive. For example, a format string of YYYY will not return anything, since it won't match any of the case labels.
You should also specify each valid option within the expression, rather than relying on two or more matches of any characters from a specified group. For example, try using the format string yyyymmdd, which will return nothing.
return f.replace(/(yyyy|mmmm|mmm|mm|dddd|ddd|dd|hh|nn|ss|a\/p)/gi,
function($1)
{
switch ($1.toLowerCase())
{
"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer
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hmm... thanks. you're right, and your suggestions work.
"There is a strength in the union even of very sorry men." - Homer
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Some may find this small addition useful:
return f.replace(/(yyyy|mmmm|mmm|mm|dddd|ddd|dd|hh|nn|ss|a\/p|sup)/gi,
case 'sup':
switch (d.getDate())
{
case 1:
case 21:
case 31:
return "st";
case 2:
case 22:
return "nd";
case 3:
case 23:
return "rd";
default:
return "th";
}
}
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Hey what a great idea. You can also group all the cases with a mod operation:
case 'sup':
switch (d.getDate() % 10)
{
case 1: return "st";
case 2: return "nd";
case 3: return "rd";
default: return "th";
}
Be careful when using format specifiers, though; "sup" may occur in the format string in a phrase; that's why I came up with "a/p" i.o. simply "ap".
Thanks, I'm glad it helped you!
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No you can't - instead of 11th, 12th and 13th, your code would return 11st, 12nd and 13rd!
"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer
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Too bad you're right. Ok, so I guess a switch is in order.
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Why not just use this?
switch ( ( d.getDate() % 100 > 3 && d.getDate() % 100 < 21 ) ? 0 : d.getDate() % 10)
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If it works, that's fine!
I would save some d.getDate() calls by setting up a variable, though. Not that users will notice, but programmers should!
There is no spoon.
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Ok, I changed the 'sup' format specifier with 's/p' and replaced the switch with a math operation:
case 's/p': var i = d.getDate() % 10; return 'thstndrd'.substr(2 * (i < 4) * i, 2);
You see, i (date mod 10) ranges from 0 to 9, but only 1, 2 and 3 have specific ordinal suffixes, so with a little math, and in a fashion similar to a choose statement in VB, I got rid of the switch statement for (hopefully) faster execution.
The math goes as follows: (i < 4) yields true for 0, 1, 2, 3 and false for everything else; fortunately for us, booleans yield 1 or 0 when used in arithmetic operations (in VB, 'true' actually equals -1). So this simple expression filters out the 'uninteresting' cases.
Next, we need the actual i value to pinpoint each case, that's why we multiply. This is also why we calculate and store i ahead of time, for we'll use it twice in the expression.
The rest involves doubling the value to get a 2-char index into the strange string we sub into, which is nothing but the ordinal suffixes, th st nd rd.
Incidentally, I realized you would need another date specifier to avoid presenting '06th', that is, skip the zero fill. But then again this datepart specifier itself might be enough (or maybe a 5d, ddddd that is) if you simply prepend the date.
Again, I just had fun figuring out an alternative to the switch. Richard Deeming corrected this anyway by pointing out that we'll get 11st i.o. 11th, 12nd and 13rd which are totally wrong; I guess the switch is in order, or an even messier math op.
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