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Ever seen Chris Maunder unintentionally post a typo that made his post funny or embarrassing? Quote it and link to it here so that the rest of us can make fun of him! 
Fixign now. | But who's fixing the fixign? |
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If my members have split personality disorder then it's polite not to disciminate against them
Kinda reminds me of that weapon from "I Come in Peace" where the alien would shoot CD's from his arm.
Fixign now. | But who's fixing the fixign? |
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Fixign now.
But who will fix his fix? Note: this happens to be my current signature. 
Fixign now. | But who's fixing the fixign? |
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Any personal attacks, nny spam, any advertising, any trolling, or any abuse of the rules will result in your account being removed.
So I guess spam that contains A's, B's, or C's is OK?
Driven to the ARMs by x86.
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Actually, that would be more of a statement, not a quetion.
Apparently, Chris knows the difference between statements and birds.
Martin Fowler wrote: Any fool can write code that a computer can understand. Good programmers write code that humans can understand.
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We had to kick the main DB server while moving a log file to a new disk cluster on te SAN
Awwww, Chris names hardware after his relatives. How cute! I wonder what the initials SAN stand for. Samantha Anne Nancy? Aunty Sam is now the SAN named SAN.
Martin Fowler wrote: Any fool can write code that a computer can understand. Good programmers write code that humans can understand.
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I hope my answer was impartial and measured and that my distaste for those who make money purely off people's ignorance and not from any atual services rendered didn't come through too strongly. atually.....
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An intereting idea. Not too difficult, either. I'll add it to the TODO. Well, Interesting one from Chris.
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Reply to this thread to share code with me.
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This code is to help clarify some code I mentioned in reply to a comment posted by SAKryukov.
class MyClass
{
private:
int x1;
int x2;
public:
MyClass() : x1(ExpensiveOperation(2) + 1), x2(ExpensiveOperation(2) + 2)
{
int a = ExpensiveOperation(2);
x1 = a + 1;
x2 = a + 2;
};
int ExpensiveOperation(int x)
{
return x + 2;
}
};
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After working with it for a few months, I'm an Umbraco master.
If asking your question on http://our.umbraco.org/ doesn't get you any responses, ask your question on this thread. I might even create an article or tip/trick to help you out.
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