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A C# Implementation of Douglas-Peucker Line Approximation Algorithm

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6 Jun 2007MIT 156.6K   3.5K   60   39
DP Line approximation algorithm is a well-known method to approximate 2D lines. It is quite fast, O(nlog_2(n)) for a n-points line and can drastically compress a data curve. Here, a fully OOP implementation is given.

Introduction

I have found multiple implementations of the Douglas-Peucker algorithm but not in any .NET language, so I decided to port it over. Jonathan de Halleux has a wonderful explanation here.

Background

I needed to reduce polygons size to display on a map based on zoom levels.

Using the Code

The code included is complete and should run out of the box in Visual Studio 2005. If it does not, please let me know.

C#
/// <summary>
/// Uses the Douglas Peucker algorithm to reduce the number of points.
/// </summary>
/// <param name="Points">The points.</param>
/// <param name="Tolerance">The tolerance.</param>
/// <returns></returns>
public static List<Point> DouglasPeuckerReduction
    (List<Point> Points, Double Tolerance)
{
    if (Points == null || Points.Count < 3)
    return Points;

    Int32 firstPoint = 0;
    Int32 lastPoint = Points.Count - 1;
    List<Int32> pointIndexsToKeep = new List<Int32>();

    //Add the first and last index to the keepers
    pointIndexsToKeep.Add(firstPoint);
    pointIndexsToKeep.Add(lastPoint);

    //The first and the last point cannot be the same
    while (Points[firstPoint].Equals(Points[lastPoint]))
    {
        lastPoint--;
    }

    DouglasPeuckerReduction(Points, firstPoint, lastPoint, 
    Tolerance, ref pointIndexsToKeep);

    List<Point> returnPoints = new List<Point>();
    pointIndexsToKeep.Sort();
    foreach (Int32 index in pointIndexsToKeep)
    {
        returnPoints.Add(Points[index]);
    }

    return returnPoints;
}
    
/// <summary>
/// Douglases the peucker reduction.
/// </summary>
/// <param name="points">The points.</param>
/// <param name="firstPoint">The first point.</param>
/// <param name="lastPoint">The last point.</param>
/// <param name="tolerance">The tolerance.</param>
/// <param name="pointIndexsToKeep">The point index to keep.</param>
private static void DouglasPeuckerReduction(List<Point> 
    points, Int32 firstPoint, Int32 lastPoint, Double tolerance, 
    ref List<Int32> pointIndexsToKeep)
{
    Double maxDistance = 0;
    Int32 indexFarthest = 0;
    
    for (Int32 index = firstPoint; index < lastPoint; index++)
    {
        Double distance = PerpendicularDistance
            (points[firstPoint], points[lastPoint], points[index]);
        if (distance > maxDistance)
        {
            maxDistance = distance;
            indexFarthest = index;
        }
    }

    if (maxDistance > tolerance && indexFarthest != 0)
    {
        //Add the largest point that exceeds the tolerance
        pointIndexsToKeep.Add(indexFarthest);
    
        DouglasPeuckerReduction(points, firstPoint, 
        indexFarthest, tolerance, ref pointIndexsToKeep);
        DouglasPeuckerReduction(points, indexFarthest, 
        lastPoint, tolerance, ref pointIndexsToKeep);
    }
}

/// <summary>
/// The distance of a point from a line made from point1 and point2.
/// </summary>
/// <param name="pt1">The PT1.</param>
/// <param name="pt2">The PT2.</param>
/// <param name="p">The p.</param>
/// <returns></returns>
public static Double PerpendicularDistance
    (Point Point1, Point Point2, Point Point)
{
    //Area = |(1/2)(x1y2 + x2y3 + x3y1 - x2y1 - x3y2 - x1y3)|   *Area of triangle
    //Base = v((x1-x2)²+(x1-x2)²)                               *Base of Triangle*
    //Area = .5*Base*H                                          *Solve for height
    //Height = Area/.5/Base

    Double area = Math.Abs(.5 * (Point1.X * Point2.Y + Point2.X * 
    Point.Y + Point.X * Point1.Y - Point2.X * Point1.Y - Point.X * 
    Point2.Y - Point1.X * Point.Y));
    Double bottom = Math.Sqrt(Math.Pow(Point1.X - Point2.X, 2) + 
    Math.Pow(Point1.Y - Point2.Y, 2));
    Double height = area / bottom * 2;

    return height;
    
    //Another option
    //Double A = Point.X - Point1.X;
    //Double B = Point.Y - Point1.Y;
    //Double C = Point2.X - Point1.X;
    //Double D = Point2.Y - Point1.Y;
    
    //Double dot = A * C + B * D;
    //Double len_sq = C * C + D * D;
    //Double param = dot / len_sq;
    
    //Double xx, yy;
    
    //if (param < 0)
    //{
    //    xx = Point1.X;
    //    yy = Point1.Y;
    //}
    //else if (param > 1)
    //{
    //    xx = Point2.X;
    //    yy = Point2.Y;
    //}
    //else
    //{
    //    xx = Point1.X + param * C;
    //    yy = Point1.Y + param * D;
    //}
    
    //Double d = DistanceBetweenOn2DPlane(Point, new Point(xx, yy));
}

Points of Interest

The code is not overly complicated. It was fun to port this algorithm, since all I feel I do nowadays is hold business' hands to help them try and solve business problems that there is no consensus on.

History

  • Beta 1

License

This article, along with any associated source code and files, is licensed under The MIT License


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Comments and Discussions

 
GeneralDo you know offhand if the result of this algorithm is the same/different.... Pin
sherifffruitfly6-Jun-07 11:28
sherifffruitfly6-Jun-07 11:28 
GeneralRe: Do you know offhand if the result of this algorithm is the same/different.... Pin
CraigSelbert6-Jun-07 15:27
CraigSelbert6-Jun-07 15:27 
GeneralCode question Pin
DocJim4-Jun-07 8:46
DocJim4-Jun-07 8:46 
GeneralRe: Code question Pin
CraigSelbert6-Jun-07 8:30
CraigSelbert6-Jun-07 8:30 
GeneralNeat...Yeah...New algorithm Pin
jconwell25-May-07 4:50
jconwell25-May-07 4:50 
GeneralRe: Neat...Yeah...New algorithm Pin
CraigSelbert25-May-07 15:40
CraigSelbert25-May-07 15:40 
GeneralTake a look here Pin
D_Guidi25-May-07 3:32
D_Guidi25-May-07 3:32 
GeneralRe: Take a look here Pin
CraigSelbert25-May-07 15:49
CraigSelbert25-May-07 15:49 
That is nice, I can't believe that after performing google search for a c# implementation of the Douglas-Peucker algorith I did not find this.

Thanks for the information.

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