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Here is the complete code without ajax functionality. You didn't mention in the question if you wanted to display result without loading the php page.The login.html could looks like this:

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> 
<html>
<head>
<script type = "text/javascript">

function validate(){
    if((f1.login.value == "") || (f1.password.value == ""))
    {
        alert("you must enter your name and password");
	return false;
    }
    else
    {    
	return true;
    }
}

</script>  
</head> 
<body>
<form  id ="f1"  action = "validate.php" method="post" onsubmit ="return validate(this);">
User Name <input  type ="text"  name = "login"/> <br />
Password <input  type ="password" name ="password"/> <br />
<input type = "submit"  value ="login"/>
</form> 
</body> 
</html>

The validate.php could look like this:

<?php
// fetching username and password
$userName = $_REQUEST["login"];
$userPassword = $_REQUEST["password"];
	
// using regular expressions to evaluate username
if(preg_match("/^[a-zA-Z][a-zA-Z0-9_]+$/", $userName, $matches)	)
{
    CheckWithDatabase($userName,$userPassword);
}
	
function CheckWithDatabase(&$usr, &$pw)
{
    // connecting to the database 
    mysql_connect("localhost", "userleon", "Pa55word") or die(mysql_error()); 
    mysql_select_db("students") or die(mysql_error()); 
    $data = mysql_query("SELECT login, password FROM login_password") or die(mysql_error());  
    while($info = mysql_fetch_array( $data )) 
    { 
         if( ($usr == $info['login']) && ( $pw == $info['password'] ))
	{
            echo "Thank you for logging in";
            // two choices offered on successful login
            echo "<form><input type=\"radio\" name=\"choice\" value=\"Add a new student\">Add a new student<br/><input type=\"radio\" name=\"choice\" value=\"Remove a student\"/>Remove a student</form>";
	}
	else
	{
            // GO BACK link
            echo "<a href=\"javascript:history.go(-1)\">GO BACK</a>";
            // javascript displays message
            echo "<script type=\"text/javascript\">alert(\"wrongpassword and/or login please try again\");</script>";
	}
    } 
}
?>

Hope it answers your question Smile | :)

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modified 25 Nov '12 - 20:15.

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