sorry but you solution didnt work,
there is problem in in this statement a[i]>a[i+1] ,when i be 5 ,it is in a>a, so compiler search for a and dont found,so here gave me the problem ,and by the way what is a[i]>a[i+1] i didnt get it
iknow that but i want to sort array as the code show but compiler when a[i] reach the final one a it compare it with a which it is not exist , i want to it stop compare when it reach the final index is there any code that could help me???
the arrays index no start with zero, and you enter here 5 element in array, so the last elent index no is 4
and you take loop upto 5 index no hense it raised error array index out of bound
1) IF you store just one object, use List, if you have two object key and value use Map.
2) List is ordered, your objects will be stored in the order on which they are inserted, Map is not ordered, unless you use sorted ones.
I tried to load a simple jsp page from an android application using the WebView.loadUrl();
But can't able to load the page. The error message is: Web page not available.The webpage at http://localhost/SampleJsp is temporarily down or it may have been moved to new address.
My aim is to access a jsp page from an android application.
When I searched the net i got the information that its possible with WebView.loadUrl() method.
But when I tried it in my application I got the error that Webpage not available. But the jsp application is running and i'm getting the page, but through android, it's error.