2 extra alerts produced at the beginning as 2 other div's exist, I don't understand why

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XML

<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
    <title>Dom Manipulation Methods</title>
    <%-- ** What are jquery DOM manipulation methods--%>
    <%-- ** How to set, retrieve, remove attribute values using jquery--%>
    <script src="Scripts/jquery-1.4.1.min.js" type="text/javascript"></script>
    <script type="text/javascript">
        //https://api.jquery.com/category/manipulation/
        // $('div').attr('title')       // displays only the first matching element found
//        $('div').attr('title', 'New DIV Title');        // to set just add second paramenter
        $(document).ready(function () {
            $('div').each(function (i) {
                $(this).attr('title', 'div' + (i + 1) + ' Title');
            });
            $('div').each(function () {
               alert( $(this).attr('title'));
            });
        });
    </script>
</head>
<body>
    <form id="form1" runat="server">
    <div id="div1" title="My DIV1">
        DIV 1
    </div>
    <div id="div2" title="My DIV2">
        DIV 2
    </div>
    </form>
</body>
</html>

Posted 11-Aug-15 9:02am

rbvol

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Comments

ZurdoDev 11-Aug-15 15:46pm

2 alerts come because of $('div').each. The $('div') selects all divs and then you call .each() so it runs for each div in your page.

What is it that you want?

Sergey Alexandrovich Kryukov 11-Aug-15 15:54pm

Did you try to use JavaScript debugger? :-)
—SA

kellyapt1 11-Aug-15 17:54pm

As RyanDev has indicated, using $('div').each will pop up an alert for all of the divs on the page. To have an alert for a specific div use the ID of the div like this:

$('#div1').each(function () {
alert( $(this).attr('title'));
});

3 solutions

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ZurdoDev · Answer 1 · 2015-08-12T01:30:00

Solution 1

As mentioned in the comments, you are using .each on your divs so for each div you will get that alert.

Posted 12-Aug-15 1:30am

ZurdoDev

rbvol · Answer 2 · 2015-08-14T03:37:00

I find out the solution to my problem. ASP.NET add these two input elements within div. This is why it my previous code was picking these extra 2 divs. What I did to solve the issue was wrap my html code within a main div and call $('#main div').each.

XML

<div>
<input type="hidden" name="__VIEWSTATE" id="__VIEWSTATE" value="/wEPDwULLTE2MTY2ODcyMjlkZAWMcFIVrd603vMUvq/dpg+m8qr3" />
</div>
<div>
    <input type="hidden" name="__VIEWSTATEGENERATOR" id="__VIEWSTATEGENERATOR" value="EF932D07" />
</div>

rbvol · Answer 3 · 2015-08-12T06:23:00

Solution 2

Thank you for your feed back...I understand what the code is supposed to do just return 2 divs, but is returning 4. And the page doesn't have more than 2 divs.

Posted 12-Aug-15 6:23am