What this mean actually arithmetic overflow error converting expression to data type datetime.

Question

1.00/5 (1 vote)

See more:

C#

Arithmetic overflow error converting expression to data type datetime.

What I have tried:

SqlCommand cmd1 = new SqlCommand("insert into Attendence values(@Engi_Profile_ID,@In_Date_Time,@In_Date_Only,@Out_Date_Time,@Reason,@Remark,@Flag)", con);

{
SqlCommand cmd1 = new SqlCommand("insert into Attendence values(@Engi_Profile_ID,@In_Date_Time,@In_Date_Only,@Out_Date_Time,@Reason,@Remark,@Flag)", con);
cmd1.Parameters.AddWithValue("@Engi_Profile_ID", txtID.Text.ToString());

}

cmd1.ExecuteNonQuery(); then give error actually Arithmetic overflow error converting expression to data type datetime.

Posted 14-Apr-16 0:58am

ashishpne

Updated 14-Apr-16 1:50am

Add a Solution

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

ZurdoDev · Answer 1 · 2016-04-14T01:49:00

Solution 1

It means whatever you are trying to put into a datetime parameter is way too big. Just debug your code and you'll see what the values are. Pretty quick and simple to fix.

Posted 14-Apr-16 1:49am

ZurdoDev

F-ES Sitecore · Answer 2 · 2016-04-14T01:50:00

Solution 2

Convert txtID.Text to a DateTime type using DateTime.TryParse, or DateTime.TryParseExact (google for examples) and add the DateTime variable to the parameter instead.

Posted 14-Apr-16 1:50am

F-ES Sitecore