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import java.util.ArrayList;
 
class HashingTest
{
	public static void main(String a[])
	{
		ArrayList ar=new ArrayList();
		ArrayList ar2=new ArrayList();
		
		ar.add(4);
		ar.add(5);
		ar.add(6);
 
		ar2.add(4);
		ar2.add(5);
		ar2.add(6);
		
		System.out.println("Value of ar[0] is "+ar.get(0)+ " & hashcode          
                is"+ar.hashCode());
		System.out.print("Value of ar2[0] is "+ar2.get(0)+ " & hashcode                
                is"+ar2.hashCode());
		
	
	}
	
}
 
Output :-
Value of ar[0] is 4 & hashcode is33796
Value of ar2[0] is 4 & hashcode is33796
 

 
In the above program, i have created 2 instances of class ArrayList as "ar & ar2".
By hashing theory, no two different instances have similar hashcode. but when i run this program i got same output for both instances .Got confused Frown | :-( ...
Can Anyone put some light on this ?
Posted 29-Sep-11 21:28pm

1 solution

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Solution 1

Hash computations operate on the objects data contents so it will compute the hash for the value "4" every time as both are the same integers.
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