convert 2d array to List

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Hi to all I'm new in C# and programming and my problem is to convert a 2d-array into a

List<int[]>

.
My goal is to store in list items the rows from the array. What I've tried so far is the above

C#

public static List<int[]> GetMyNumbers(int[,] result)
       {

           int[,] res = result;

           int length = res.GetUpperBound(0) + 1;
           int width = res.GetUpperBound(1) + 1;
           int[] rows = new int[width];
           List<int[]> numberArrays = new List<int[]>();

           for (int i = 0; i < result.Length / width; i++)
           {
               for (int k = 0; k < width; k++)
               {
                   rows[k] = res[i, k];
                   Console.Write(rows[k]);
               }
               Console.WriteLine();
               numberArrays.Add(rows);//this doesn't fill the list properly..It adds to all list items the last row of the 2d array

           }

           return numberArrays;


       }

The result array is the following..

C#

int[,]result={{ 2,3,7 }, {2,3,5 } ,{2,3,6},{ 2,4,7 }, {2,4,5 } ,{2,4,6}};

I have to mention here that the above array could change both in items and size, so I'm looking for some solution that would fit in any array size.
Thanks in advance for both your time and your help!!!

Posted 2-Nov-11 0:20am

katerinaPapathak

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2 solutions

Solution 1

C#

for(int i=0;i<result.length;i++)>
{
   int[] newRow = new int[result[i]];
   for(j=0;j<result[i].length;j++)>
   {
      newRow[j] = result[i,j];
   }
   list.add(newRow);

}

mark as answer if solves your problem

Posted 2-Nov-11 0:33am

Pandya Anil

Updated 2-Nov-11 0:34am

v2

Comments

katerinaPapathak 2-Nov-11 6:43am

have you tried running the above code?? the command int[] newRow=new int [result[i]]; throughs me error and at the begging of the loop tells to create an array with the size of the element 0 of result but the result is [,] array..could you explain the sequence??

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LanFanNinja · Accepted Answer · 2011-11-02T01:35:00

Solution 2

Try this:

C#

int[,] result = {{ 2,3,7 }, {2,3,5 } ,{2,3,6},{ 2,4,7 }, {2,4,5 } ,{2,4,6}};
List<int[]> numberArrays = new List<int[]>();
for (int i = 0; i < result.GetLength(0); i++)
{
    int[] temp = new int[result.GetLength(1)];
    for (int n = 0; n < temp.Length; n++)
    {
        temp[n] = result[i, n];
    }
    
    numberArrays.Add(temp);
}

Posted 2-Nov-11 1:35am

LanFanNinja

Updated 2-Nov-11 1:36am

v2

Comments

katerinaPapathak 2-Nov-11 7:44am

thank you very much!!!!that worked fine!!!!could you point out what i did wrong??
just for further knowledge...thanks again for your time and solution..

LanFanNinja 2-Nov-11 8:19am

Well it seems that rows is being passed to numberArrays.Add() by reference and by declaring int[] rows outside of the first for loop all references to rows inside of the numberArrays List was being updated with the new values. Screwy I know but that is whats happening. So by declaring rows (temp) inside the first for loop a new array is being created every iteration so the reference being passed to numberArrays is that of a new array and not the same one. All the rest of your code was fine.

katerinaPapathak 2-Nov-11 9:12am

thank you once again!!!!