how to print reverse of odd numbers in a DataList?

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VB

1   2   3   4   5
1   4   9   16  25
1   3   5   7   9
9   7   5   3   1

i have done 1st three rows.but not able to display the 4th(9,7,5,3,1)row.i know the method...any one help??

C#

if(!IsPostBack)
        {
            DataTable dt=new DataTable();
            DataRow dr;
            dt.Columns.Add(new DataColumn("Numbers",typeof(Int32)));
            dt.Columns.Add(new DataColumn("Squares", typeof(Int32)));
            dt.Columns.Add(new DataColumn("Odd", typeof(Int32)));
            dt.Columns.Add(new DataColumn("OddReverse", typeof(Int32)));
            for(int i=0;i<=5;i++)
            {
                dr=dt.NewRow();
                dr[0]=i;
                dr[1] = Square(i);
                dr[2] = Odd(i);
                dr[3] = OddReverse(i);
                dt.Rows.Add(dr);
            }
            dlMyList.DataSource=dt;
            dlMyList.DataBind();
        }
    }

    int Square(int num)
    {
        int ans = num * num;
        return ans;
    }
    int Odd(int num)
    {
        int ans = num * 2-1;
        return ans;
    }
    int OddReverse(int num)
    {
for(num=5;num>=1;num--)

        int ans = num *2-1;
        return ans;
    }

this is the code..where should i place for loop??fr oddreverse?

Posted 5-Dec-11 22:40pm

ythisbug

Updated 5-Dec-11 23:25pm

Anuja Pawar Indore

v4

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Comments

OriginalGriff 6-Dec-11 4:49am

If I understood what your problem was, possibly.
As it is, I don't know what you are trying to do, or with what, or what is going wrong.
Edit your question, and provide a better example (before, after as it should be, after as it is) and a relevent code fragment.
Use the "Improve question" widget to edit your question and provide better information.

ythisbug 6-Dec-11 4:52am

if(!IsPostBack)
{
DataTable dt=new DataTable();
DataRow dr;
dt.Columns.Add(new DataColumn("Numbers",typeof(Int32)));
dt.Columns.Add(new DataColumn("Squares", typeof(Int32)));
dt.Columns.Add(new DataColumn("Odd", typeof(Int32)));
dt.Columns.Add(new DataColumn("OddReverse", typeof(Int32)));
for(int i=0;i<=5;i++)
{
dr=dt.NewRow();
dr[0]=i;
dr[1] = Square(i);
dr[2] = Odd(i);
dr[3] = OddReverse(i);
dt.Rows.Add(dr);
}
dlMyList.DataSource=dt;
dlMyList.DataBind();
}
}

int Square(int num)
{
int ans = num * num;
return ans;
}
int Odd(int num)
{
int ans = num * 2-1;
return ans;
}
int OddReverse(int num)
{
int ans = num *2-1;
return ans;
}
this is the code..but i unable to display reverse of odd number..where should i place the for loop for odd reverse m nt able to get it..

OriginalGriff 6-Dec-11 5:07am

Put that in your question - along with the other info.

1 solution

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CPallini · Accepted Answer · 2011-12-05T23:34:00

Solution 1

use

C#

int OddReverse(int num)
{
   int ans = (6-num) *2-1;
   return ans;
}

BTW the main (and unique ) loop should be:

C#

for(int i=1; i<=5; i++)

Posted 5-Dec-11 23:34pm

CPallini

Comments

Wendelius 6-Dec-11 5:47am

Excellent, my 5

CPallini 6-Dec-11 6:03am

Thank you.

ythisbug 6-Dec-11 6:16am

thanks

CPallini 6-Dec-11 6:18am

You are welcome.