Left Button Down Sensitivity

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2.00/5 (1 vote)

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I have a OnRButtonDown function..and it will show a dialog box if the point fit with my nodes (X,Y in DOUBLE) in an Array...

C++

if((post.x>=nodeX[j]-5 || post.x<=nodeX[j]+5) && (post.y>=nodeY[j]-5 || post.y<=nodeY[j]+5))

that code doesn't works, all area i click is TRUE for it...
I want when i press left button nearby the node it'll show the dialog as well...

C++

if(post.x==nodeX[j] && post.y==nodeY[j])

Code above makes me tired to precise the pointer..
Is there any simple solution? or MFC provide a specific code for it?
Thank You

Posted 2-Jan-12 17:29pm

Kay Andrian Fikar

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Style-7 · Accepted Answer · 2012-01-02T21:14:00

Solution 1

Must be:
if( post.x >= nodeX[j]-5 && post.x <= nodeX[j]+5 && post.y >= nodeY[j]-5 && post.y <= nodeY[j]+5)

Why nodeX and nodeY - use POINT node[] or structure
Use PtInRect function
http://msdn.microsoft.com/en-us/library/dd162882(v=vs.85).aspx

Posted 2-Jan-12 21:14pm

Style-7

Comments

CPallini 3-Jan-12 3:47am

Good solution and advice, my 5. Why don't you properly format posted code?

Jochen Arndt · Accepted Answer · 2012-01-02T21:22:00

Solution 2

Try this and think about the logical operators:

if(post.x>=nodeX[j]-5 && post.x<=nodeX[j]+5 && post.y>=nodeY[j]-5 && post.y<=nodeY[j]+5)

If you would use int vars, you may also create a CRect for your sensitive area and use CRect::PtInRect().

Posted 2-Jan-12 21:22pm

Jochen Arndt