CMD command with arguments

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3.00/5 (1 vote)

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I am trying to run a command (from C# ) that looks like this
c:\MyCommand /LOAD >c:\temp\mycommand.txt

This is what I tried but the file is not created.

Process Process = new Process();
Process.StartInfo.Arguments = " >c:\\mycommand.txt";
Process.Start("MyCommand","/LOAD");

does not pipe the output to a file

//also tried the following
//Process.Start("MyCommand /LOAD",">c:\temp\mycommand.txt");
//Process.Start("MyCommand", " /LOAD >c:\temp\mycommand.txt");

Any help is greatly appreciated

Posted 26-Feb-12 18:19pm

picasso2

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Chandrakantt · Answer 1 · 2012-02-26T19:01:00

One another method to redirect the output of an executable is shown below:

using System;
using System.Collections.Generic;
using System.Text;
using System.Diagnostics;
using System.IO;

namespace ConsoleTest
{
    class Program
    {
        static void Main(string[] args)
        {
            ProcessStartInfo start = new ProcessStartInfo();
            start.FileName = @"systeminfo.exe"; // Specify exe name.
            start.UseShellExecute = false;
            start.RedirectStandardOutput = true;
            using (Process process = Process.Start(start))
            {
                StreamWriter sw = new StreamWriter(@"C:\textinfo.txt");

                using (StreamReader reader = process.StandardOutput)
                {
                    string result = reader.ReadToEnd();
                    sw.Write(result);
                    sw.Close();
                }
            }
        }
    }
}

Dave Kreskowiak · Answer 2 · 2012-02-26T18:37:00

Solution 2

Redirection doesn't work if you don't launch it inside a CMD.

So, your command line would look like this:

CMD.exe /C "<fullpathto>\MyCommand.exe /LOAD > C:\Temp\MyCommand.txt"</fullpathto>

Keep in mind that normal users are not allowed to create file in C:\Temp in Windows 7. Use the path returned by the TEMP environment variable instead. It will end up in the Temp folder in the users profile.

Posted 26-Feb-12 18:37pm

Dave Kreskowiak

Comments

Sergey Alexandrovich Kryukov 27-Feb-12 1:26am

Good point about bad file location. I voted 4 because this is still not a solution.
Basically, the right one (with couple of my notes) is the solution 3, please see.
--SA

Dean Oliver · Answer 3 · 2012-02-26T18:27:00

C#

Process Process = new Process();
Process.StartInfo.Arguments = " >c:\\mycommand.txt";
Process.Start("MyCommand.exe","/LOAD >c:\temp\mycommand.txt");

try that.

Have you tried executing the command in the command prompt first. If so does it work? Before we start to diagnose if something is wrong with the code.

CMD command with arguments

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Solution 2

Solution 1

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