a program to check if the number is related to fibonacci series or not

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can any one help me by finding a way
how to right a program to check whether the number belongs to fibonacci series
without counting the whole fibonacci numbers?????

fibonacci series math code is
f(x)=f(x-1)+f(x-2) x>=2

the counting code is easy but i need to check a number entered by user!!!!

Posted 28-Mar-12 19:00pm

yamen-nassif

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4 solutions

Solution 4

As suggested by Resmi the mathemaical approach is the best for your question.

However, if memory is not a constaint and you want your application for repetitive use.
I suggest go for a simplified approach of Dynamic programming

1)Keep a Dynamic Array []
2)Whenver input is given do a binary search in Array
3) if found , jump to step 5
4)If not found compute the series till you get the Fibonacci number starting from N-1 and Nth element in the Array and add the result to Array
5) send the response to user

This will make your program much faster and performance will increase with the input list.

Best Regards,
Raina

Posted 29-Mar-12 16:26pm

aayushraina

Solution 1

That's described in wikipedia:
http://en.wikipedia.org/wiki/Fibonacci_number[^], chapter "Recognizing Fibonacci numbers".

Posted 28-Mar-12 20:24pm

Bernhard Hiller

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chandanadhikari · Accepted Answer · 2012-03-28T20:59:00

hi,
ask the user to input a number, store that in a variable.In a loop,
start generating fibonacci number one by one using your formula and compare each number with users input, if this is same as users input,then display mesage accordingly.
if its NOT same,then generate next number of the series and go on till you get a match.
this is a basic logic flow.I hope you can improve on this and code yourself.

happy coding !!

Resmi Anna · Accepted Answer · 2012-03-29T00:26:00

suppose you input the value to the variable N

Then following code checks whther N belongs to Fib series

C++

double dRes1 = sqrt((5*pow(N, 2))-4);
int nRes1 = (int)dRes1;
double dDecPoint1 = dRes1 - nRes1;

double dRes2 = sqrt((5*pow(N, 2))+4);
int nRes2 = (int)dRes2;
double dDecPoint2 = dRes2 - nRes2;

if( !dDecPoint1 || !dDecPoint2 )
{
    cout<< N << " is a Fib series member";
}
else
{
    cout<< N << " Not Fib series member";
}

a program to check if the number is related to fibonacci series or not

4 solutions

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