how to convewrt 10 digite number in a series without useing array we can use only for loop/if-else/switch statment

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Java

public class LengthOfLongsSerise {
    public static void main(String[] args) {

        int a ;
        int cnt1 = 0;
        int cnt2 = 0;
        int cnt3 = 0;
        int cnt4 = 0;
        a=(int)(Math.random()*100);
        int j=0;
        int p=55;
        for(int i=1;i<=10;i++){
         j=a=(int)(Math.random()*100);
        j++;
      System.out.println(j);
        }
      }

int this care if auto generate numbers(4,5,6,2,8,12,14,16,5,9)then here is three serise
like = 1st- 4,5,6
second-2,8,12,14,16
3rd- -5,9
i want this out put is second is max serise length outputis only =4

.Help me plz .

Posted 30-May-12 13:33pm

kushal.choudhary

Updated 30-May-12 22:32pm

Richard MacCutchan

v3

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Sergey Alexandrovich Kryukov 30-May-12 20:19pm

Huh? Serise..?! Please spell-check it -- hard to understand what are you talking about.
--SA

kushal.choudhary 30-May-12 20:29pm

series (EXAMPLE = LIKE MISSION IMPOSSIBLE MOVIE SERIES)

in this program
1st =4,5,6
2ns = 2,8,12,14,16
3rd = 5,9 GOT IT SIR..??

Sandeep Mewara 31-May-12 1:14am

Homework?

1 solution

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Richard MacCutchan · Answer 1 · 2012-05-30T22:39:00

Something like:

count = 3
for (i = 1; i <= count; ++i)
{
    print "series ", i, ": "
    lastNumber = 0
    while (true)
    {
        number = Random()
        if (number > lastNumber)
        {
            print number, ", "
            lastNumber = number
        }
        else
        {
            print "\n"
            break;
        }
    }
}