Execute the next line in shell script after starting a process from shell script

Question

0.00/5 (No votes)

See more:

Hello,

I am trying to run one mono application as service. When I start from terminal
using the following method
service MyTestApp start

It strts as servive I can view its log porcess etc and prints
Starting MyTestApp

and wait the app in terminal not showing Started MyTestApp and I can possible to type next command only when I press Ctrl+C. How I can solve this

how to execute the next line after starting mono application in shell script.

my sample script is given below

Bash

#!/bin/sh
#/etc/init.d/MyTestApp


APP_NAME="MyTestApp"

case "$1" in
  start)


        echo "Starting $APP_NAME"
	mono MyTestApp.exe
 	echo "Started $APP_NAME"
       
    ;;
  stop)

       
    ;;
  *)
    echo "Usage: /etc/init.d/$APP_NAME {start|stop}"
    exit 1
    ;;
esac

exit 0

Posted 25-Jul-12 1:07am

Arun Kumar K S

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Richard MacCutchan · Accepted Answer · 2012-07-25T02:11:00

Solution 1

I don't know about Mono, but in normal Linux/UNIX you would just put the program to run in the background by appending the & to the call thus:

PERL

mono MyTestApp.exe &

However this may well mean that the mono process runs in the background but the other process does not. A few tests should tell you which.

Posted 25-Jul-12 2:11am

Richard MacCutchan

Comments

Arun Kumar K S 25-Jul-12 9:20am

is this execute this line echo "Started $APP_NAME"

Richard MacCutchan 25-Jul-12 10:26am

I assume so, what happens when you try it?

Arun Kumar K S 26-Jul-12 22:39pm

thanks..................