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How to make child and parent window active in windows application?
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Hi
 
I am working on windows application.
I have two windows basically.
when i open the child window,I am not able to access the main window.
I want to access both the child window and main window at time.
It should be active.
How to do that?
 

Regards
Froxy
Posted 12 Sep '12 - 1:09
froxy1K
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Comments
vijay bisht - 12 Sep '12 - 8:00
inspite of showdialogue use only frm.show

2 solutions

You can enable the parent window using this:
private void Form_Activated(object sender, System.EventArgs e)
{
    if (this.Owner != null)
    {
        this.Owner.Enabled = true;
    }
}
Or use the following code to open your form:
Form newForm = new ChildForm();
newForm.Show(this);
 

 
--Amit
  Permalink  
Posted 12 Sep '12 - 1:15
_Amy38.1K
What do you mean by access ? Accessing the dialog as a user perspective or programmer perspective.
 
Anyway, considering from user perspective, it seems that you've created the Model dialog. You've to create Modeless dialog for that.
 
Go through this[^] article.
  Permalink  
Posted 12 Sep '12 - 1:17
Malli_S16.9K
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