DataGridView LinkButton open PathURL

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C#

.NET

C#4.0

.NET4

Hi,

In datagridview have three columns.

======================================================
ImageType|| imageurl(linkButton)|| delete(button)||
======================================================
Face ||d:\Temp\Face.jpg || delete||
FullImage ||d:\Temp\FullImage .jpg || delete||
======================================================

// 
// ImageType // 

this.ImageType.HeaderText = "ImageType";
 this.ImageType.Name = "ImageType"; 
// 

// Attachment //

this.Attachment.HeaderText = "Attachment"; 
this.Attachment.Name = "Attachment"; 
this.Attachment.Resizable = System.Windows.Forms.DataGridViewTriState.True; this.Attachment.SortMode = System.Windows.Forms.DataGridViewColumnSortMode.Automatic; 
this.Attachment.Width = 130; 
// 

// DeleteImg // 

this.DeleteImg.FillWeight = 50F; 
this.DeleteImg.HeaderText = "Delete"; this.DeleteImg.Name = "DeleteImg"; 
this.DeleteImg.Resizable = System.Windows.Forms.DataGridViewTriState.True; this.DeleteImg.Width = 50; 

// code : 
if (File.Exists(imagePath)) { string result = Path.GetFileNameWithoutExtension(imagePath); string[] row = new string[] { result, imagePath }; dataGridViewAttachment.Rows.Add(row); }

how to write code to open image this pathUrl(d:\Temp\Face.jpg ).
Karthikeyan,