decode query string in classic asp

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hi all,

i have following string with "+" sign in the end. I have used javascript escape function to encode "+" as it is. But when i execute this url, i am not getting "+" leading wrong result. How to decode this string so that i will get proper string?

http://xyz.com/test.asp?id=SF&pnam=722%25%20IT%20Sf%20Con%3C100%3E2year21+

Thanks

Posted 29-Oct-12 3:34am

PleaseHelpCP

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Thomas Daniels · Answer 1 · 2012-10-29T03:45:00

Solution 1

Try this:

http://xyz.com/test.asp?id=SF&pnam=722%25%20IT%20Sf%20Con%3C100%3E2year21%2B

The URL encoding char for a + sign is %2B

Hope this helps.

Posted 29-Oct-12 3:45am

Thomas Daniels

Updated 30-Oct-12 0:48am

v3

Comments

PleaseHelpCP 30-Oct-12 6:06am

Tried this but not working. I am using frames. If i check page properties, i get correct url i.e. with encoded 2B. But if i try to retrieve using request.querystring, its not showing blank space.

Thomas Daniels 30-Oct-12 6:09am

What's the code you use?

PleaseHelpCP 30-Oct-12 6:19am

tried using replace function of javascript

Thomas Daniels 30-Oct-12 6:20am

I need the code that you use. Otherwise, I can't know exactly what you do.

PleaseHelpCP 30-Oct-12 6:26am

tried 2 ways.

1. pnam = Decode(Encode(request.querystring("pnam")))

Function Decode(sIn)
dim x, y, abfrom, abto
Decode="": ABFrom = ""

For x = 0 To 25: ABFrom = ABFrom & Chr(65 + x): Next
For x = 0 To 25: ABFrom = ABFrom & Chr(97 + x): Next
For x = 0 To 9: ABFrom = ABFrom & CStr(x): Next

abto = Mid(abfrom, 14, Len(abfrom) - 13) & Left(abfrom, 13)
For x=1 to Len(sin): y=InStr(abto, Mid(sin, x, 1))
If y = 0 then
Decode = Decode & Mid(sin, x, 1)
Else
Decode = Decode & Mid(abfrom, y, 1)
End If
Next
End Function

' USE: location.href="nextpage.asp?" & encode("sParm=" & sData)

Function Encode(sIn)
dim x, y, abfrom, abto
Encode="": ABFrom = ""

For x = 0 To 25: ABFrom = ABFrom & Chr(65 + x): Next
For x = 0 To 25: ABFrom = ABFrom & Chr(97 + x): Next
For x = 0 To 9: ABFrom = ABFrom & CStr(x): Next

abto = Mid(abfrom, 14, Len(abfrom) - 13) & Left(abfrom, 13)
For x=1 to Len(sin): y = InStr(abfrom, Mid(sin, x, 1))
If y = 0 Then
Encode = Encode & Mid(sin, x, 1)
Else
Encode = Encode & Mid(abto, y, 1)
End If
Next
End Function

and other is javascript replace
str.replace(str,"+","####")

Thomas Daniels 30-Oct-12 6:30am

I know the solution!
You need to change the URL into this:
http://xyz.com/test.asp?id=SF&pnam=722%25%20IT%20Sf%20Con%3C100%3E2year21%2B

Change the & into &
I updated my answer.

PleaseHelpCP 30-Oct-12 6:38am

is it to changes & to & or vise-versa?

Thomas Daniels 30-Oct-12 6:38am

Just change & into &

PleaseHelpCP 30-Oct-12 6:46am

but there is no & used anywhere. please correct me if i am wrong.

Thomas Daniels 30-Oct-12 6:48am

No, you're right. I typed my answer with &
And that was wrong.

PleaseHelpCP 30-Oct-12 6:59am

this solution isn't working

Thomas Daniels 30-Oct-12 7:01am

But why you need to encode the parameter?
Maybe it's working without the encoding.

PleaseHelpCP 30-Oct-12 7:04am

without encoding also its giving same result. so tried encoding.

Thomas Daniels 30-Oct-12 7:10am

And what does request.querystring("pnam") return?

PleaseHelpCP 30-Oct-12 7:33am

same.

PleaseHelpCP 30-Oct-12 7:34am

i mean with + sign