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I entered 2 dates. Example 01/01/2012 and 01/01/2013 as mm/dd/yyyy format.
I want to calculate date difference between entered date as (this much of)year (this much of)month (this much of)days. Please help me to solve this.
Posted 4-Nov-12 20:55pm
CSR89508
n.podbielski at 5-Nov-12 2:58am

Soooooooo.... You want this in SQL or Javascript?
Ramdas.C.S at 5-Nov-12 3:28am

SQL
n.podbielski at 5-Nov-12 4:14am

You did not wrote which sql you want. If TSQL see answer Aarti.
But I would strongly recommend you to do this in code, not in SQL since it is for data storage not for calculating anything.
Milind Thakkar at 5-Nov-12 4:58am

Consider start and end date as '2012-01-10' and '2015-05-21'. query in solution 1 will give result as 21 days,3 years, 40 months.

Query in solution 2(mine) below will give result as 3 year, 4 month, 11 days, which is the correct difference between the two dates.

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## Solution 3

Hello

Use this javascript
```function CalculateDays1() {
t1 = document.getElementById('Fromdate').value;
t2 = document.getElementById('Todate').value;
if (t2 != '' && t1 != '') {
//Total time for one day
var one_day = 1000 * 60 * 60 * 24;
//Here we need to split the inputed dates to convert them into standard format
//for furter execution
var x = t1.split("/");
var y = t2.split("/");
//date format(Fullyear,month,date)

var date1 = new Date(x[2], (x[0] - 1), x[1]);

var date2 = new Date(y[2], (y[0] - 1), y[1])
var month1 = x[0] - 1;
var month2 = y[0] - 1;

//Calculate difference between the two dates, and convert to days
_Diff = Math.ceil((date2.getTime() - date1.getTime()) / (one_day)) + 1;

document.getElementById('TextBoxID-where you want to show calucate day').value = _Diff;
document.getElementById('HiddenFiledID').value = _Diff;
}
}
```

Now just take one hidden field in .aspx page.

```<asp:hiddenfield id="totDays1" runat="server" xmlns:asp="#unknown" />
```
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## Solution 2

I believe, you want difference in year, month and date between two days,

The query will go like
```select (datepart(yyyy,@firstDate) - datepart(yyyy,@secondDate)) as Diffyear
select (datepart(mm,@firstDate) - datepart(mm,@secondDate)) as DiffMonth
select (datepart(dd,@firstDate) - datepart(dd,@secondDate)) as DiffDays```

If you want better user experience for the user, you may want to check whether first date is greater than second date before above query, if second date is greater than first date, you should re-arrange the query to avoid showing -1 year or -2 month or -15 days kind of display.

Hope that helps
Milind
Ramdas.C.S at 5-Nov-12 5:44am

how can i get the answer as 1year2month15days in a single row?
Milind Thakkar at 5-Nov-12 5:48am

very simple. instead of three select, write 1
select (datepart(yyyy,@firstDate) - datepart(yyyy,@secondDate)) as Diffyear,
(datepart(mm,@firstDate) - datepart(mm,@secondDate)) as DiffMonth,
(datepart(dd,@firstDate) - datepart(dd,@secondDate)) as DiffDays

Hope that helps. If it solved your problem, mark it as solution and/or upvote.
Milind
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## Solution 1

see below example
```select datepart(day,'2012-01-10') as days
select datediff(yyyy,'2012-01-10','2012-01-01') as years
select datediff(m,'2012-01-10','2012-01-01')-(datediff(yyyy,'2012-01-10','2012-01-01')*12) as months```
pass parameter like this
```select datepart(day,@EndDate) as Days
select datediff(yyyy,@StartDate,@EndDate) as years
select datediff(m,@StartDate,@EndDate)-(datediff(yyyy,@StartDate,@EndDate)*12) as months```
Note : Date Format is always yyyy-MM-dd in sql.
Happy Coding!
v5
Ramdas.C.S at 5-Nov-12 4:03am

The date entered is dynamic, and the period of date may of any value. The answer here specifies only in a fixed period.
Aarti Meswania at 5-Nov-12 4:08am

see updated solution
n.podbielski at 5-Nov-12 4:14am

Just use declare SQL statement with viariables for those to dates.
Ramdas.C.S at 5-Nov-12 4:31am

But in the case of leap year what will we do?
Aarti Meswania at 5-Nov-12 4:33am

yes I was also thinking for that
and you will feel smile with this simple answer as I feel when I got it
:)
just check this updated Final solution, As you wished
Milind Thakkar at 5-Nov-12 4:57am

consider start and end date as '2012-01-10' and '2015-05-21'. Your query will give result as 21 days,3 years, 40 months. Which is NOT as what OP wants.
Query in my solution below will give result as 3 year, 4 month, 11 days, which is the correct difference between the two dates.
Aarti Meswania at 5-Nov-12 5:07am

you are right i forget to edit for months
thanks for suggestion :)
It's updated