generating letters from two user given values

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i have been trying to write a method that generates random letters between two given char values. So far i believe the best way is to convert the char characters to ascii values then compare them with the user input and make a for loop between those 2 values. My problem is i dont know how to compare the values after they have been converted here is my code so far:

Java

public void add (char fromChar, char toChar){
        Random a = new Random();
       char[] characters = { 'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
       int start =65;
       for(int i =0; i<characters.length;>         characters[i] = start;
         start++;
         
         
       }     
       for(int i = fromChar; i<tochar;>           System.out.println(a.nextInt(fromChar,toChar);
       }
        
    }

[edit]Spurious bold removed, Code block added - OriginalGriff[/edit]

Posted 17-Nov-12 19:14pm

diego14567

Updated 17-Nov-12 20:33pm

OriginalGriff

v2

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Richard MacCutchan · Accepted Answer · 2012-11-17T22:38:00

Solution 1

You need to set a seed based on some arbitrary value, then call the nextInt() method with a limiting range. Something like:

Java

int range = toChar - fromChar;
int seed = fromChar * toChar;
Random rr = new Random(seed);
for (int i = 0; i < 10; ++i) {
    char randomChar = (char)(fromChar + rr.nextInt(range));
    System.out.println("Next character: " + randomChar);
}

Posted 17-Nov-12 22:38pm

Richard MacCutchan

Comments

diego14567 18-Nov-12 8:27am

thanks man i never would have thought about doing it this way

Richard MacCutchan 18-Nov-12 8:34am

You're welcome.