Switch Case (return byte[])

Question

2.00/5 (1 vote)

See more:

I have a method that will check a character input, and according to the entered character will return an array of bytes consisting of 1's and 0's
(i.e) in case 2 is passed to the method I will get.
b[0] = 0
b[1] = 0
b[2] = 0
b[3] = 0
b[4] = 1
b[5] = 0

The method I tried to implement is returning the ascii equivalent of the 1's and 0's
Is there another way instead of using the below code?

C#

private byte[] determineOutput(char c)
        {
            //byte[] b = new byte[6];
            string s="";
            System.Text.Encoding enc = System.Text.Encoding.ASCII;

            switch (c)
            {
                case '0':
                    s = "000000";
                    break;
                case '1':
                    s= "000001";
                    break;
                case '2':
                    s = "000010";
                    break;
                case 'A':
                    s = "001010";
                    break;
                default:
                    Console.WriteLine("Invalid Characther");
                    break;
            }

            byte[] b = enc.GetBytes(s);

            for (int i = 0; i < b.Length; i++)
            {
                Console.Write(b[i]);
            }
            Console.WriteLine();

            return (b);
        }

Posted 18-Nov-12 0:10am

spanner323

Add a Solution

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

OriginalGriff · Answer 1 · 2012-11-18T00:48:00

Solution 1

Have you looked at using a BitArray[^] instead?

Alternatively, you could do it like this:

C#

byte[] outp = new byte[5];
for (int i = 0; i < 5; i++)
   {
   outp[i] = (byte) inp & 0x20;
   inp << 1;
   }
return outp;

Posted 18-Nov-12 0:48am

OriginalGriff

spanner323 · Answer 2 · 2012-11-18T01:41:00

This method solved the issue

C#

private byte[] determineOutput(char c)
        {
            byte[] b = new byte[6];
            //byte b = 11;

            switch (c)
            {
                case '0':
                    b = new byte[6] { 0, 0, 0, 0, 0, 0 };
                    break;
                case '1':
                    b = new byte[6] { 0, 0, 0, 0, 0, 1 };
                    break;
                case '2':
                    b = new byte[6] { 0, 0, 0, 0, 1, 0 };
                    break;
                case 'A':
                    b = new byte[6] { 0, 0, 1, 0, 1, 0 };
                    break;
                default:
                    Console.WriteLine("Invalid Characther");
                    break;
            }


            for (int i = 0; i < b.Length; i++)
            {
                Console.Write(b[i]);
            }
            Console.WriteLine();

            return (b);
        }