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Can any one please tell me how to find all words from a particular directory which contains a,e,i,o,u in order.

Ex abstancious. Here 'a' followed by 'a' followed by 'i' followed by 'o' followed by 'u'. Vowels never repeated.

I have cat /home/user1/tmp/* | grep [aeiou]

But it's not displaying my expected answer.

Please help.

Thanks in advance.
Posted 20-Nov-12 18:23pm

1 solution

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Solution 1

Your regular expression is just looking for any single vowel. You want something more like "^[^aeiou]*a[^aeiou]*e[^aeiou]*i[^aeiou]*o[^aeiou]*u[^aeiou]*$" I think (assuming it must have all of them). This one searches for zero or more consonants, a, zero or more consonants, e, etc.
srmohanr at 21-Nov-12 5:12am
Please refine the answer more. Because even I am getting the output 'unfacetiousness'. But this is not my scenario.

Please help
lewax00 at 21-Nov-12 10:06am
I updated it to match only whole lines. You should take the time to learn regular expressions, they can be very useful.

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