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Hello,
I have a vb program, a form with a picturebox, I want on mouse left click to change the image and set another one, I want to use an if then statement so ir will change picture according to the pic in use. My problem I get an error "operator '=' is not defined for types 'system.drawing.image'...", how can I change the code to work?

        If e.Button = Windows.Forms.MouseButtons.Left Then
               If PictureBox1.Image = My.Resources._1 Then
                PictureBox1.Image = My.Resources._2
            End If
        End If      
Posted 26-Dec-12 7:38am
Comments
Rddezh at 26-Dec-12 12:57pm
   
Hi! You should check the data type of My.Resources._2.

1. Insert brakepoint in the line, where seting value to picturebox image
2. Debug the program
3. Put mouse over the My.Resources._2 and check if it is the Image, Bitmap or any other type, that can be directly converted to Image.

I never used VB too much, but I'm familiar with c# ;)
Member 3892343 at 26-Dec-12 13:16pm
   
the error is being in the "if pocturebox1.image = my.recources._1" and it is in design time and I cannot debug, it is not in the change image "picturebox1.image = my.recources._2", I found some code "if referenceequals(picturebox1.image,my.recources._1) = true" it does not have an error but not working at runtime, any help, C# is similar to vb.

1 solution

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Solution 1

Have you tried the equals method from Image ObjecT?

If PictureBox1.Image.Equals(My.Resources._1) Then
    'Do your stuff
End If

Hope this helps.
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