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Providing "create new" option in the dropdownlist.
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See more: C#ASP.NET
I have two asp.net webpages:
1.Form.aspx
2.Subform.aspx
 

->I have a dropdownlist bound to a sql datasource.when i run the form.aspx,the dropdownlist successfully shows all the names from the database.
 
->But what i want My dropdownlist to also show an option "create new" along with the database records.
So that when i select "create new" from the dropdownlist, the second webpage i.e.Subform.aspx gets open.
Posted 27 Dec '12 - 0:41
Member 9581909407
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4 solutions

as you said to show,
"create new" along with the database records.
 
A simplest way is
 
modify query as below
select 0 as id, 'Create New' as name
union all
select id,name from tblnm
Happy Coding!
Smile | :)
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Posted 27 Dec '12 - 0:49
Aarti Meswania19.3K 
<asp:DropDownList ID="DropDownList1" AppendDataBoundItems="true" runat="server" DataSourceID="SqlDataSource1" DataTextField="state" DataValueField="state">
 
    <asp:ListItem Text="(Select a State)" Value="" />
 
</asp:DropDownList>
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Posted 27 Dec '12 - 1:05
Manohar_manu780
The Dropdownlist Items can be added through codebehind...But, one main point is
 
you cant add the items in page load.
 
Ex: ddl_type.Items.Insert(0,"Create New");
 
It can be added on Page_PreRenderComplete stage of the Page Life Cycle.
 
The Items Will Be Bounded in this stage of Page Life Cycle.
 
Reason: The Page_PreRenderComplete() here the datasource id will be appended to the required controls.
 
For Detailed Description Go through this link.
http://msdn.microsoft.com/en-us/library/ms178472(v=vs.100).aspx[^]
 
To Open new page Enable the Autopostback = true and in code behind on dropdownlist selected index change.
 
All The Best
With Regards
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Posted 27 Dec '12 - 1:18
Nandakishorerao2.4K
Edited 27 Dec '12 - 1:19
v2
Just Do the follow:
 
this will be on page load of the page :
 
       if(!ispostback)
       {
                
        DataSet ds = new DataSet();
        SqlDataAdapter myda = new SqlDataAdapter("select field name from table", connection object);
        myda.Fill(ds);
        drop_down1.DataSource = ds;
        drop_down1.DataValueField = "field name";
        drop_down1.DataBind();
        drop_down1.Items.Insert(0, new ListItem("Create New", "0"));
      }
 
 
if any problem, please post it.
 

Mitesh
  Permalink  
Posted 27 Dec '12 - 1:18
Mitesh Machhi40
Edited 27 Dec '12 - 1:23
v3
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