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int main( ) {
 char str[] = { 48, 49, 50, 51, 52, 53, 54};
 int *p = (int *) (str + 1);
 char *pStr = (char *)p;
 printf("%c\n", *pStr);

what is the o/p ?
in *p what gets stored and *pStr what gets stored?
Posted 16-Jan-13 0:17am

1 solution

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Solution 1

Try it!
Compile it, run it and see.
Output is "1"
p contains a pointer to the second byte in the array of characters
So does pStr.
It might be different if you try to actually use p as a pointer to an int and retrieve an integer value from it - some systems will fail, because the int pointer is (probably) not word aligned. But char values don't have to have any particular alignment, so that works fine.
Andreas Gieriet at 16-Jan-13 8:11am
My 5!
Key is, as you say, as long as you do not de-reference the non-aligned pointer, all is fine.

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