How to concatenate 2 data in database and show it in a listbox

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Hello! I have a database that has a firstname and lastname field. I want to retrieve the two fields and bind it into a listbox.

I've manage to bind the datas in a listbox with a single field only. With code like this:

void LoadGrid()
        {
            MySqlConnection sqlcon = new MySqlConnection(strConnString);
            sqlcon.Open();
            sqlcmd = new MySqlCommand("SELECT lastname from userdbase", sqlcon);
            da = new MySqlDataAdapter(sqlcmd);
            dt.Clear();
            da.Fill(dt);
            if (dt.Rows.Count > 0)
            {

                ListBox1.DataSource = dt;
                ListBox1.DataTextField = "lastname";
                ListBox1.DataBind();
            }
        }

But I don't know how to insert another field and concatenate it with this first one. Any help? Thanks.

Example:
firstname || lastname
----------------------
Kristine || Ramos
Mary || Mariano

Output in listbox will be:
Kristine Ramos
Mary Mariano

Posted 24-Feb-13 23:23pm

jmpapa

Updated 24-Feb-13 23:29pm

v2

Add a Solution

3 solutions

Solution 1

hi buddy

this will that you want....
just set properties as per requirement of yours..

C#

try
               {

                   con.Open();
                   string str = "select CONCAT(1stname, ' (' ,lastname,')') AS mixname from userdbase where pfno='" + sd.epfno + "'";
                    da = new MySqlDataAdapter(str, con);
                   ds = new DataSet();
                   da.TableMappings.Add("table", "userdbase");
                   da.Fill(ds, "userdbase");
                   this.listBox1.DataSource = this.ds;
                   this.listBox1.DisplayMember = "userdbase.mixname ";
                   this.listBox1.ValueMember = "userdbase.mixname";
                   //listBox1.MultiColumn = true;
                  con.Close();
                  da.Dispose();

               }
               catch (Exception ex)
               {
                   MessageBox.Show("Error" + ex.Message);
               }

happy to help

Posted 24-Feb-13 23:42pm

Shubh Agrahari

Updated 24-Feb-13 23:45pm

v2

Comments

jmpapa 25-Feb-13 6:01am

Thank you Shubh! I applied your code in mine. And I came up with this:

sqlcon.Open();
string str = "select CONCAT(firstname, ' (' ,lastname,')') AS mixname from userdbase";
da = new MySqlDataAdapter(str, sqlcon);
DataSet ds = new DataSet();
da.TableMappings.Add("table", "empdependentd");
da.Fill(ds, "empdependents");
this.ListBox1.DataSource = this.ds;
this.ListBox1.DataTextField = "empdependents.mixname ";
this.ListBox1.DataValueField = "empdependents.mixname";
sqlcon.Close();
da.Dispose();

However, there's an error with this line:
this.ListBox1.DataSource = this.ds;
in the ds to be specific. What may caused this?

Shubh Agrahari 25-Feb-13 6:09am

what error showing??

Shubh Agrahari 25-Feb-13 6:12am

tried with this...??
void LoadGrid()
{
MySqlConnection sqlcon = new MySqlConnection(strConnString);
sqlcon.Open();
sqlcmd = new MySqlCommand("select CONCAT(1stname, ' (' ,lastname,')') AS mixname from userdbase ", sqlcon);
da = new MySqlDataAdapter(sqlcmd);
dt.Clear();
da.Fill(dt);
if (dt.Rows.Count > 0)
{

ListBox1.DataSource = dt;
ListBox1.DataTextField = "lastname";
ListBox1.DataBind();
}
}

jmpapa 25-Feb-13 7:03am

Got this error:
DataBinding: 'System.Data.DataRowView' does not contain a property with the name 'lastname'.

Shubh Agrahari 25-Feb-13 7:05am

put your last one code here.......that showing error

jmpapa 25-Feb-13 7:34am

it's just the same with the code you posted above. The error is in this:

ListBox1.DataSource = dt;
ListBox1.DataTextField = "lastname";
ListBox1.DataBind();

I've also tried to use "firstname" in exchange to lastname, but still got the same error.

Shubh Agrahari 25-Feb-13 8:09am

buddy one thing is that if you have 2 column one is firstname and 2nd is lastname then you concating it by this query "select CONCAT(1stname, ' (' ,lastname,')') AS mixname from userdbase " then now you have to write this
this.ListBox1.DataTextField = "userdbase.mixname ";
this.ListBox1.DataValueField = "userdbase.mixname";
mixname is a virtual name that making to column as one at runtime.....

Shubh Agrahari 25-Feb-13 8:11am

sqlcon.Open();
string str = "select CONCAT(firstname, ' (' ,lastname,')') AS mixname from userdbase"; da = new MySqlDataAdapter(str, sqlcon);
DataSet ds = new DataSet();
da.TableMappings.Add("table", "userdbase");
da.Fill(ds, "userdbase");
this.ListBox1.DataSource = this.ds;
this.ListBox1.DataTextField = "userdbase.mixname ";
this.ListBox1.DataValueField = "userdbase.mixname";
sqlcon.Close();
da.Dispose();

here userdbase is your database name and also mixname is a virtual name that making to column as one at runtime... try this

jmpapa 25-Feb-13 9:26am

finally, I made it! I used this code:

MySqlConnection sqlcon = new MySqlConnection(strConnString);
sqlcon.Open();
string sqlcmd = "select CONCAT(firstname, ' (' ,lastname,')') AS mixname from userdbase";
da = new MySqlDataAdapter(sqlcmd,sqlcon);
dt.Clear();
da.Fill(dt);
if (dt.Rows.Count > 0)
{

ListBox1.DataSource = dt;
ListBox1.DataTextField = "mixname";
ListBox1.DataBind();
}

It's a combination of your given code and my previous code. Thank you very much for your help and patience.

Shubh Agrahari 25-Feb-13 9:32am

yap its ma pleasure buddy but also nice attempt by you also....its good quality to give peek of potential for trouble shooting....go ahead nice career waiting for us....

Solution 2

Try This->

C#

void LoadGrid()
        {
                MySqlConnection sqlcon = new MySqlConnection(strConnString);
                sqlcon.Open();
                sqlcmd = new MySqlCommand("SELECT (ISNULL(firstname, '') + '' + ISNULL(lastname,         '')) FROM userdbase", sqlcon);
                da = new MySqlDataAdapter(sqlcmd);
                dt.Clear();
                da.Fill(dt);
                if (dt.Rows.Count > 0)
                {
 
                  ListBox1.DataSource = dt;
                  ListBox1.DataTextField = "lastname";
                  ListBox1.DataBind();
                }
         }

Posted 25-Feb-13 0:31am

Singh_Vinay

Updated 25-Feb-13 2:56am

v3

Comments

jmpapa 25-Feb-13 7:02am

got this error:
Incorrect parameter count in the call to native function 'ISNULL'

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jmpapa · Accepted Answer · 2013-02-25T03:28:00

I came up with this code. And it works fine.

MySqlConnection sqlcon = new MySqlConnection(strConnString);
            sqlcon.Open();
            string sqlcmd = "select CONCAT(firstname, ' (' ,lastname,')') AS mixname from userdbase"; 
            da = new MySqlDataAdapter(sqlcmd,sqlcon);
            dt.Clear();
            da.Fill(dt);
            if (dt.Rows.Count > 0)
            {

                ListBox1.DataSource = dt;
                ListBox1.DataTextField = "mixname";
                ListBox1.DataBind();
            }