I am doing this right aren't I, hex conversion

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Hi All,

I am try to decode a bit string (ie: 0000,0000,0000,0000) using a hex value for example
0x0400 = 1024 (dec) I need to pick out bits in the past I have done this via the following

C#

// bit 0
if ((Hexvalue2 & 0x0001) == 0)
{
    //MessageBox.Show("bit 0 set");
}
else
{
    //MessageBox.Show("bit 0 not set");
}

using the pattern 0001,0002,0004,0008 and then 0010, 0020 and so on, I have done this in Turbo C++ (Borland) and it has worked can this method be applied to C# as I can read one byte correctly and the other I can seem to. If it is a zero a label gets one value and if not a label gets another.

Glenn
(Why, Why, I spent half of last night playing with this!)

Posted 27-Feb-13 3:30am

glennPattonWork3

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BC @ CV 27-Feb-13 9:36am

Yes. You can use bitwise operators to check for bit flags.

Bit Wise Operators

Bit Flag Enums

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Richard MacCutchan · Answer 1 · 2013-02-27T03:37:00

Solution 1

Your expression is not correct, it should be

C#

if (Hexvalue2 & 0x0001)
{
    MessageBox.Show("bit 0 is set");
}

etc.

Posted 27-Feb-13 3:37am

Richard MacCutchan

Comments

glennPattonWork3 27-Feb-13 9:46am

Hmmm, If I do the above it will only check for the bit being set I also need to take action on the not set case, also won't that cause problems with trying to convert a ulong to a boolean?
I guess I should said so in the question but Hexvalue2 is a ulong.

Richard MacCutchan 27-Feb-13 10:11am

Well for the other case you can either use the appropriate 'not' operator to reverse the test, or add an else clause to your if statement. As to whether the value is a short or long, it makes no difference, the compiler will generate the correct code.

Richard MacCutchan 27-Feb-13 10:13am

Supplementary note: I'm not sure where the confusion is coming from here, these operators are exactly the same as used in C, C++ etc.