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<?php
$conn = mysql_connect("localhost", "root", "") or die("Error on Server!!!");
mysql_select_db("merged", $conn) or die("Error on Database!!!");
 
$query = "SELECT * FROM admin WHERE uname=? AND upass=SHA1(?)";
 

?>
 
I have this code. Now i'want make login form using $_POST...
 
I did login form...
 
how to make login...
Posted 20-Mar-13 5:44am

1 solution

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Solution 1

Hello,
 
Your code for checking the login might look like
$conn = mysql_connect("localhost", "root", "") or die("Error on Server!!!");
mysql_select_db("merged", $conn) or die("Error on Database!!!");
 
$usrId = $_POST["txtUserId"]; 
$usrPass = $_POST["txtPass"];
$query = sprint("SELECT * FROM admin WHERE uname = '%s' AND upass = SHA1('%s')", mysql_real_escape_string($usrId), mysql_real_escape_string($usrPass));
$result = mysql_query($query);
if (!$result) {
    $message = 'Invalid query: ' . mysql_error() . "\n";
    die($message);
}
?>
Regards,
  Permalink  

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