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Dear All,


I have my xml file with rootnode as "Base" and I have my attribute "Name" available in the root node itself. I need to find out my attribute value located in my root node. How could I proceed, please help me ASAP. For your reference I hereby providing you a sample.

<Baseclass ID="5" Name="Raj">

</Baseclass>
Posted 22-May-13 20:19pm
Edited 22-May-13 20:22pm
v2
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Solution 1

Try this
XDocument xDoc = XDocument.Load("path to xml");
var TagIds = xDoc.Descendants()
                .Elements()
                .Where(e => 
                            e.HasAttributes && 
                            e.Name.LocalName.Equals("Baseclass") && 
                            e.Attribute("ID") != null)
                .Select(e => e.Attribute("ID").Value);


Hope this helps
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v2
Comments
Jameel Moideen 23-May-13 1:33am
   
I have updated my answer..please try that
rahulaaditya 24-May-13 9:50am
   
Many thanks to you Jameel for your help.
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Solution 2

Dim tempPath As String = FolderBrowserDialog1.SelectedPath & "\" & ListBox1.Items(x).ToString

Dim xSid = From xattr In xDoc.Descendants("Baseclass") _
Select att = xattr.Attribute("Name").Value
sSID = xSid.ElementAt(0).ToString 'SID value
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