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Why does my array contain all nulls?

System.out.println(loo); -> This will show what's inside the array properly
System.out.println(tokFix[i]); -> While this will show all null's




public static String[] parseFixMsg(String fixMsg1,String fixMsg2){
    int i = 0;
    int size = getArraySize(fixMsg1);
    String[] tokFix = new String[size];
    StringTokenizer st = new StringTokenizer(fixMsg2,(Character.toString((char)01))+"]");
    st.nextToken();
 

    while (st.hasMoreTokens()) {
 
        tokFix[i] = st.nextToken();
        String loo = tokFix[i];
        i++;
        <big>System.out.println(loo);
        System.out.println(tokFix[i]); </big>
Posted 12-Jul-13 7:08am

1 solution

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Solution 1

You incremented i before checking. Of course the next item is empty, you haven't populated it yet.
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0 Sergey Alexandrovich Kryukov 679
1 OriginalGriff 455
2 Andy Lanng 245
3 CPallini 242
4 Maciej Los 225
0 OriginalGriff 8,864
1 Sergey Alexandrovich Kryukov 8,245
2 CPallini 5,189
3 Maciej Los 4,726
4 Mika Wendelius 3,606


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