Brain Burning Question

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Hi guys

I want to the ask a question for the brain burning ;-P

Write a function for decide about the odd or even numbers, this function should get a number and return "Number is odd" or "Number is even", with out the using any condition .....

Best Regards.
Homay

Posted 10-Sep-13 0:37am

Aydin Homay

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Comments

nv3 10-Sep-13 6:54am

Take a look at how numbers are being represented in the binary system and the answer will be very obvious.

pasztorpisti 10-Sep-13 9:04am

A number is odd only if its least significant bit (whose value is (2^0)==1) is set, all the other bits (2^1, 2^2,...) are even so their sum is also even. You can get the value of this bit with the following expressions: (number % 2) OR (number & 1). Most compilers optimize (number % 2) to (number & 1) that is usually faster on most machines, integer remainder with a divisor that is a power of 2 can always be reduced into and & instruction.

4 solutions

Solution 1

even-or-odd-without-using-condtional-statement/[^]

Hope it is helpful enough...

Posted 10-Sep-13 0:57am

TheUltimateDebugger

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CPallini · Accepted Answer · 2013-09-10T00:58:00

Solution 2

C++

const char * myBrainHurts(int n)
{
  static const char * ans[] = {"Number is even", "Number is odd" };
  return ans[n % 2];
}

Posted 10-Sep-13 0:58am

CPallini

Stefan_Lang · Accepted Answer · 2013-09-10T01:54:00

Solution 4

This should do:

C++

#include <iostream>
const char* foo() {
   int some_number;
   std::cout << "please enter number!" << std::endl;
   std::cin >> some_number;
   return "Number is odd";
}

(note that there was no requirement to link the output to the input in any way! ;-p )

Posted 10-Sep-13 1:54am

Stefan_Lang

Comments

CPallini 10-Sep-13 7:59am

OK, but it should anyway provide all the output range :-D

Aydin Homay 10-Sep-13 8:14am

Good job guys

Stefan_Lang 10-Sep-13 8:58am

You mean I should return "Number is odd or even"? ;-)

CPallini 10-Sep-13 9:23am

Or...Both! :-D

CB Sharma · Accepted Answer · 2013-09-10T01:06:00

Solution 3

C#

public string EvenOrOdd(int num)
        {
            string[] array2 = new string[] { "Even", "Odd" };

            num = num % 2;
            return ("Entered number is  " + array2[num]);
        }

Posted 10-Sep-13 1:06am

CB Sharma