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VB
' OK button
   Private Sub OK_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles OK.Click
       Dim con As New OleDbConnection("Provider=Microsoft.jet.oledb.4.0;data source=C:\Users\Jill\Desktop\saddbase\Sadsystem\Sadsystem\bin\Debug\tenant.mdb")
       Dim cmd As OleDbCommand = New OleDbCommand("SELECT * FROM info WHERE TN_ID = '" & UsernameTextBox.Text & "' AND Password = '" & PasswordTextBox.Text & "' ", con)
       con.Open()
       Dim sdr As OleDbDataReader = cmd.ExecuteReader()
       ' If the record can be queried, Pass verification and open another form.
       If (sdr.Read() = True) Then
           MessageBox.Show("The user is valid!")

           Me.Hide()
       Else
           MessageBox.Show("Invalid Tenant ID or password!")
       End If


When I run the program there's an error in cmd.ExecuteReader(). *Data type mismatch in criteria expression* please help how to fix this error.
Posted
Updated 1-Mar-18 17:36pm

I'm guessing your username column is not really named TN_ID, but something closer to Username. The TN_ID column is probably your primary key and you are trying to use equality to compare it with a text value, which is a data type mismatch.
 
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TN_ID could be a numeric field (possibly ID field as Ron suggested). Check for it's datatype in the database. If it is numeric field then the error makes sense as you are passing string value "UsernameTextBox.Text" into it.

If TN_ID is the username field then
"Integer.Parse(UsernameTextBox.Text)" would do, provided username is combination of numbers, also change it is userid to make more sense.

else if TN_ID is not the username field then
change the TN_ID to right field name (keep in mind the datatype conversion).

else, if TN_ID should hold username which in turns contains alphabets, convert the TN_ID field to varchar (if numeric).
 
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what is the data type of the tn_id and password i don't know
please check the datatypes
If TN_ID is integer and password is string then try
("SELECT * FROM info WHERE TN_ID = " & UsernameTextBox.Text & " AND Password = '" & PasswordTextBox.Text & "' ", con)

if TN_ID is string and password is string then try this
("SELECT * FROM info WHERE TN_ID = '" & UsernameTextBox.Text & "' AND Password = '" & PasswordTextBox.Text & "' ", con)
 
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in Access DB, when we use select Query, we have to use TN_ID = " & UsernameTextBox.Text & " instead of TN_ID = '" & UsernameTextBox.Text & "' for number data type.
Because '" & any-value & "' is used for String value and " & any-value & " used for integer or number value from database. (') is used for Sting data. for number we should remove it like this " & any-value & "
 
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Comments
Russell.BD 24-Oct-15 10:52am    
Thanks for your clear explanation. It works for me!
Member 10295316 10-Jan-18 14:28pm    
Thanks for your Explanation. I ran into the same problem but your solution work for me
Member 15016268 9-Dec-20 4:41am    
Thankyou it works for me .

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